Step by Step solution about How to resolve the algorithm Count in octal step by step in the Go programming language

First example:

• It defines a loop that starts from int8(0) and increments i by 1 until it reaches the maximum value representable by an int8 type (which is math.MaxInt8).
• The loop prints the octal representation of i in each iteration.

Second example:

• Similar to the first example, but it uses uint16 type.
• It starts from uint16(0) and increments i by 1 until it reaches the maximum value representable by a uint16 type (which is math.MaxUint16).
• It also prints the octal representation of i in each iteration.

Third example:

• It defines a loop that starts from 0. (which is a floating-point number) and increments i by 1 in each iteration.
• It prints the octal representation of i converted to int64 in each iteration.
• The purpose of this loop is to demonstrate the behavior of floating-point numbers when they are incremented by 1. As the loop progresses, i will eventually become so large that adding 1 to it no longer changes its value, causing the loop to terminate.

Fourth example:

• It uses the big package to work with arbitrary-precision integers.
• It defines a loop that starts from big.NewInt(0) and increments i by big.NewInt(1) in each iteration.
• It prints the octal representation of i in each iteration.
• The purpose of this loop is to demonstrate that the big package can be used to handle integers that are too large to fit in the default integer types provided by Go.

package main

import (
    "fmt"
    "math"
)

func main() {
    for i := int8(0); ; i++ {
        fmt.Printf("%o\n", i)
        if i == math.MaxInt8 {
            break
        }
    }
}


func main() {
    for i := uint16(0); ; i++ {  // type specified here
        fmt.Printf("%o\n", i)
        if i == math.MaxUint16 { // maximum value for type specified here
            break
        }
    }
}


import "fmt"

func main() {
    for i := 0.; ; {
        fmt.Printf("%o\n", int64(i))
        /* uncomment to produce example output
        if i == 3 {
            i = float64(1<<53 - 4) // skip to near the end
            fmt.Println("...")
        } */
        next := i + 1
        if next == i {
            break
        }
        i = next
    }
}


import (
    "big"
    "fmt"
)

func main() {
    defer func() {
        recover()
    }()
    one := big.NewInt(1)
    for i := big.NewInt(0); ; i.Add(i, one) {
        fmt.Printf("%o\n", i)
    }
}