How to resolve the algorithm Count in octal step by step in the Kotlin programming language
How to resolve the algorithm Count in octal step by step in the Kotlin programming language
Table of Contents
Problem Statement
Produce a sequential count in octal, starting at zero, and using an increment of a one for each consecutive number. Each number should appear on a single line, and the program should count until terminated, or until the maximum value of the numeric type in use is reached.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Count in octal step by step in the Kotlin programming language
-
The first line of the code specifies the version of the Kotlin compiler that was used to compile the program. In this case, it's version 1.1.
-
The second line is a function declaration. The function is named
main
and it takes an array of strings as input. This array is used to store the command-line arguments that were passed to the program when it was executed. -
The third line of the code is the body of the
main
function. It uses theforEach
method on the range(0..Byte.MAX_VALUE)
to iterate over all the values in that range. For each value, it prints the value in octal format using the%03o
format string. The%03o
format string specifies that the value should be printed as a three-digit octal number, with leading zeros if necessary. -
The fourth line of the code is the end of the
main
function.
Source code in the kotlin programming language
// version 1.1
// counts up to 177 octal i.e. 127 decimal
fun main(args: Array<String>) {
(0..Byte.MAX_VALUE).forEach { println("%03o".format(it)) }
}
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