How to resolve the algorithm Count occurrences of a substring step by step in the ARM Assembly programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Count occurrences of a substring step by step in the ARM Assembly programming language
Table of Contents
Problem Statement
Create a function, or show a built-in function, to count the number of non-overlapping occurrences of a substring inside a string. The function should take two arguments:
It should return an integer count. The matching should yield the highest number of non-overlapping matches. In general, this essentially means matching from left-to-right or right-to-left (see proof on talk page).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Count occurrences of a substring step by step in the ARM Assembly programming language
Source code in the arm programming language
/* ARM assembly Raspberry PI */
/* program strcptsub.s */
/************************************/
/* Constantes */
/************************************/
/* for this file see task include a file in language ARM assembly*/
.include "../constantes.inc"
/************************************/
/* Initialized data */
/************************************/
.data
szMessResult: .asciz "Result: "
szString: .asciz "the three truths"
szSubString: .asciz "th"
szString1: .asciz "ababababab"
szSubString1: .asciz "abab"
szCarriageReturn: .asciz "\n"
szMessStart: .asciz "Program 32 bits start.\n"
/************************************/
/* UnInitialized data */
/************************************/
.bss
sZoneConv: .skip 24
/************************************/
/* code section */
/************************************/
.text
.global main
main: @ entry of program
ldr r0,iAdrszMessStart
bl affichageMess
ldr r0,iAdrszString
ldr r1,iAdrszSubString
bl countSubString
ldr r0,iAdrszString1
ldr r1,iAdrszSubString1
bl countSubString
100: @ standard end of the program
mov r0, #0 @ return code
mov r7, #EXIT @ request to exit program
svc 0 @ perform the system call
iAdrszString: .int szString
iAdrszSubString: .int szSubString
iAdrszString1: .int szString1
iAdrszSubString1: .int szSubString1
iAdrsZoneConv: .int sZoneConv
iAdrszMessResult: .int szMessResult
iAdrszCarriageReturn: .int szCarriageReturn
iAdrszMessStart: .int szMessStart
/***************************************************/
/* count sub string of string */
/***************************************************/
/* r0 contains a string */
/* r1 contains a substring */
/* r0 return substring count */
countSubString:
push {r1-r7,lr} @ save registers
mov r4,#0 @ counter
mov r3,#0 @ index string
Mov r5,#0 @ index substring
1:
ldrb r6,[r0,r5] @ load byte of string
ldrb r7,[r1,r3] @ load byte of substring
cmp r6,r7 @ compare byte
bne 2f @ not equal
cmp r6,#0 @ string end ?
beq 3f @ yes
add r5,r5,#1 @ else increment index
add r3,r3,#1
b 1b @ and loop
2: @ characters not equal
cmp r6,#0 @ end string ?
beq 4f
cmp r7,#0 @ end substring ?
addeq r4,r4,#1 @ yes -> increment counter
mov r3,#0 @ raz index substring
add r5,r5,#1 @ increment string index
b 1b @ and loop
3: @ end string and end substring
add r4,r4,#1 @ increment counter
4: @ result display
mov r0,r4
ldr r1,iAdrsZoneConv
bl conversion10
ldr r0,iAdrszMessResult
bl affichageMess
ldr r0,iAdrsZoneConv
bl affichageMess
ldr r0,iAdrszCarriageReturn
bl affichageMess
mov r0,r4
100:
pop {r1-r7,pc}
/***************************************************/
/* ROUTINES INCLUDE */
/***************************************************/
/* for this file see task include a file in language ARM assembly*/
.include "../affichage.inc"
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