How to resolve the algorithm Count the coins step by step in the JavaScript programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Count the coins step by step in the JavaScript programming language
Table of Contents
Problem Statement
There are four types of common coins in US currency:
There are six ways to make change for 15 cents:
How many ways are there to make change for a dollar using these common coins? (1 dollar = 100 cents).
Less common are dollar coins (100 cents); and very rare are half dollars (50 cents). With the addition of these two coins, how many ways are there to make change for $1000? (Note: the answer is larger than 232).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Count the coins step by step in the JavaScript programming language
First Response:
- Provides a detailed explanation of the first function,
countcoins
, which uses dynamic programming to count the number of ways to make change for a given target amount using a specific set of coins. - Explains the algorithm, variable initialization, and recursive iteration to calculate the result.
- However, it does not mention the second and third functions.
Second Response:
- Briefly describes the second function,
countcoins
, but does not provide a detailed explanation. - Fails to explain the third function.
- Presents a different implementation of the coin change problem using dynamic programming but does not relate it to the first two functions.
Detailed Explanation:
The provided source code contains three JavaScript functions that solve the coin change problem:
1. Function countcoins
(Dynamic Programming):
- This function takes two parameters:
t
(the target amount) ando
(an array of coin denominations). - It initializes a table
t
of sizetargetsLength = t + 1
, wheretargetLength
represents the target amount plus one. - It iterates through all coins in
o
and all target values int
. - For each pair of coin and target, it accumulates the number of ways to reach that target using the current coin and previous targets.
- The result is stored in
t[targetsLength - 1]
, which represents the number of ways to make change for the target amount.
2. Function countcoins
(Recursive Permutation):
- This function is an alternative solution to the coin change problem using recursion.
- It initializes a variable
solutions
to count the number of ways to reach the target amount. - It calls a recursive function
permutate
that takes two parameters:a
(the current amount) andx
(the index of the last used coin). - The
permutate
function explores all possible combinations of coins to reach the target recursively. - When the current amount equals the target amount, it increments the
solutions
counter. - The result is returned as the number of solutions.
3. Coin Change Problem with Dynamic Programming:
- This is another implementation of the coin change problem using dynamic programming.
- It uses a table
t
of sizeamount + 1
, whereamount
is the target amount. - It initializes
t[amount]
to 0 and iterates through all coins and all target values up to the target amount. - For each pair of coin and target, it accumulates the number of ways to reach that target using the current coin and previous targets.
- The result is stored in
t[amount]
, which represents the number of ways to make change for the target amount.
Source code in the javascript programming language
function countcoins(t, o) {
'use strict';
var targetsLength = t + 1;
var operandsLength = o.length;
t = [1];
for (var a = 0; a < operandsLength; a++) {
for (var b = 1; b < targetsLength; b++) {
// initialise undefined target
t[b] = t[b] ? t[b] : 0;
// accumulate target + operand ways
t[b] += (b < o[a]) ? 0 : t[b - o[a]];
}
}
return t[targetsLength - 1];
}
countcoins(100, [1,5,10,25]);
242
function countcoins(t, o) {
'use strict';
var operandsLength = o.length;
var solutions = 0;
function permutate(a, x) {
// base case
if (a === t) {
solutions++;
}
// recursive case
else if (a < t) {
for (var i = 0; i < operandsLength; i++) {
if (i >= x) {
permutate(o[i] + a, i);
}
}
}
}
permutate(0, 0);
return solutions;
}
countcoins(100, [1,5,10,25]);
242
var amount = 100,
coin = [1, 5, 10, 25]
var t = [1];
for (t[amount] = 0, a = 1; a < amount; a++) t[a] = 0 // initialise t[0..amount]=[1,0,...,0]
for (var i = 0, e = coin.length; i < e; i++)
for (var ci = coin[i], a = ci; a <= amount; a++)
t[a] += t[a - ci]
document.write(t[amount])
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