How to resolve the algorithm Count the coins step by step in the Mathematica / Wolfram Language programming language
How to resolve the algorithm Count the coins step by step in the Mathematica / Wolfram Language programming language
Table of Contents
Problem Statement
There are four types of common coins in US currency:
There are six ways to make change for 15 cents:
How many ways are there to make change for a dollar using these common coins? (1 dollar = 100 cents).
Less common are dollar coins (100 cents); and very rare are half dollars (50 cents). With the addition of these two coins, how many ways are there to make change for $1000? (Note: the answer is larger than 232).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Count the coins step by step in the Mathematica / Wolfram Language programming language
The provided Wolfram code defines a function called CountCoins
that counts the number of ways to make change for a given monetary amount using a list of coin denominations. Here's a detailed explanation of the code:
-
CountCoins[amount_, coinlist_] :=
: This line defines theCountCoins
function, which takes two arguments:amount
, which is the monetary amount for which you want to count the number of ways to make change, andcoinlist
, which is a list of coin denominations available for making change. -
(ways = ConstantArray[1, amount];
: This line initializes an arrayways
with lengthamount
and sets all its elements to 1. TheConstantArray
function creates an array of the specified length, where each element has the given constant value. In this case, it creates an array of lengthamount
, where each element is 1. -
Do[For[j = coin, j <= amount, j++,
: This line starts aDo
loop over each coin denomination in thecoinlist
. The loop variablej
represents the current coin denomination being considered. -
If[ j - coin == 0,
: Within the innerFor
loop, it checks if the current coin denomination (j
) is equal to the amount to be changed (amount
). Ifj
is equal toamount
, it means that a single coin of denominationj
can exactly make up the desired amount, so it increments the corresponding element in theways
array by 1. -
ways[[j]] ++,
: Ifj
is not equal toamount
, it means that a single coin of denominationj
cannot make up the desired amount exactly. In this case, it adds the value stored inways[[j - coin]]
to the current element in theways
array. This step accumulates the number of ways to make change using the previous coin denominations and the current coin denomination. -
]]
,]
: These closing brackets end the innerFor
loop and the outerDo
loop. -
ways[[amount]]
: After the loops have completed, it returns the element in theways
array corresponding to theamount
index. This value represents the total number of ways to make change for the given monetary amount using the provided coin denominations.
In summary, the CountCoins
function uses dynamic programming to efficiently count the number of ways to make change for a given monetary amount using a specified list of coin denominations. It does this by populating an array ways
to store the number of ways to make change for all possible amounts up to the given amount
, and then returning the number of ways for the desired amount
from the ways
array.
Source code in the wolfram programming language
CountCoins[amount_, coinlist_] := ( ways = ConstantArray[1, amount];
Do[For[j = coin, j <= amount, j++,
If[ j - coin == 0,
ways[[j]] ++,
ways[[j]] += ways[[j - coin]]
]]
, {coin, coinlist}];
ways[[amount]])
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