How to resolve the algorithm Create an object at a given address step by step in the C programming language
How to resolve the algorithm Create an object at a given address step by step in the C programming language
Table of Contents
Problem Statement
In systems programing it is sometimes required to place language objects at specific memory locations, like I/O registers, hardware interrupt vectors etc.
Show how language objects can be allocated at a specific machine addresses. Since most OSes prohibit access to the physical memory if it is not mapped by the application, as an example, rather than a physical address, take the address of some existing object (using suitable address operations if necessary).
For example:
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Create an object at a given address step by step in the C programming language
First Code Snippet:
This code snippet demonstrates memory access and manipulation in C using pointers.
- It declares two variables:
intspace
, an integer, andaddress
, a pointer to an integer. - It assigns the address of
intspace
to the pointeraddress
(effectivelyaddress = &intspace
). - It stores the value 65535 in the memory location pointed to by
address
(i.e., inintspace
). - It prints the address, the value stored at the address, and the value of
intspace
. - It then manipulates the memory directly using pointer arithmetic to change the value stored in
intspace
. Specifically, it sets the first two bytes to 0x00 and the last two bytes to 0xFF. - It prints the address, the value stored at the address, and the value of
intspace
again.
Second Code Snippet:
This code snippet demonstrates memory access and manipulation in C using a memory-mapped I/O register.
- It includes the headers
<stdint.h>
and<stddef.h>
to access theuint32_t
data type andsize_t
for pointer arithmetic. - It defines a preprocessor macro
PORT_A
that points to a volatile 32-bit unsigned integer at memory address 0x100. - It toggles the 0th bit of the register
PORT_A
by XORing it with 0x01. - It reads the value of
PORT_A
into the variabledat
. - It calculates the address of
PORT_A
using the&
operator and stores it in the variableaddr
.
This snippet essentially allows you to access and manipulate hardware registers through a pointer-like interface, a common technique in embedded systems programming.
Source code in the c programming language
#include <stdio.h>
int main()
{
int intspace;
int *address;
address = &intspace; // address = 0x100;
*address = 65535;
printf("%p: %08x (=%08x)\n", address, *address, intspace);
// likely we must be worried about endianness, e.g.
*((char*)address) = 0x00;
*((char*)address+1) = 0x00;
*((char*)address+2) = 0xff;
*((char*)address+3) = 0xff; // if sizeof(int) == 4!
// which maybe is not the best way of writing 32 bit values...
printf("%p: %08x (=%08x)\n", address, *address, intspace);
return 0;
}
#include <stdint.h>
#include <stddef.h>
// This is a port variable located at address 0x100
#define PORT_A (*(volatile uint32_t*)0x100)
int main()
{
uint32_t dat;
size_t addr;
PORT_A ^= 0x01; // Toggle bit 0 of PORT_A
dat = PORT_A; // Read PORT_A
addr = &PORT_A; // addr = 0x100
return 0;
}
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