How to resolve the algorithm De Bruijn sequences step by step in the CLU programming language
How to resolve the algorithm De Bruijn sequences step by step in the CLU programming language
Table of Contents
Problem Statement
The sequences are named after the Dutch mathematician Nicolaas Govert de Bruijn.
A note on Dutch capitalization: Nicolaas' last name is de Bruijn, the de isn't normally capitalized unless it's the first word in a sentence. Rosetta Code (more or less by default or by fiat) requires the first word in the task name to be capitalized.
In combinatorial mathematics, a de Bruijn sequence of order n on a size-k alphabet (computer science) A is a cyclic sequence in which every possible length-n string (computer science, formal theory) on A occurs exactly once as a contiguous substring. Such a sequence is denoted by B(k, n) and has length kn, which is also the number of distinct substrings of length n on A; de Bruijn sequences are therefore optimally short. There are: distinct de Bruijn sequences B(k, n).
For this Rosetta Code task, a de Bruijn sequence is to be generated that can be used to shorten a brute-force attack on a PIN-like code lock that does not have an "enter" key and accepts the last n digits entered.
Note: automated teller machines (ATMs) used to work like this, but their software has been updated to not allow a brute-force attack.
A digital door lock with a 4-digit code would have B (10, 4) solutions, with a length of 10,000 (digits). Therefore, only at most 10,000 + 3 (as the solutions are cyclic or wrap-around) presses are needed to open the lock. Trying all 4-digit codes separately would require 4 × 10,000 or 40,000 presses.
(The last requirement is to ensure that the verification tests performs correctly. The verification processes should list any and all missing PIN codes.) Show all output here, on this page.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm De Bruijn sequences step by step in the CLU programming language
Source code in the clu programming language
% Generate the De Bruijn sequence consisiting of N-digit numbers
de_bruijn = cluster is generate
rep = null
own k: int := 0
own n: int := 0
own a: array[int] := array[int]$[]
own seq: array[int] := array[int]$[]
generate = proc (k_, n_: int) returns (string)
k := k_
n := n_
a := array[int]$fill(0, k*n, 0)
seq := array[int]$[]
db(1, 1)
s: stream := stream$create_output()
for i: int in array[int]$elements(seq) do
stream$puts(s, int$unparse(i))
end
return(stream$get_contents(s))
end generate
db = proc (t, p: int)
if t>n then
if n//p = 0 then
for i: int in int$from_to(1, p) do
array[int]$addh(seq, a[i])
end
end
else
a[t] := a[t - p]
db(t+1, p)
for j: int in int$from_to(a[t - p] + 1, k-1) do
a[t] := j
db(t + 1, t)
end
end
end db
end de_bruijn
% Reverse a string
reverse = proc (s: string) returns (string)
r: array[char] := array[char]$predict(1, string$size(s))
for c: char in string$chars(s) do
array[char]$addl(r, c)
end
return(string$ac2s(r))
end reverse
% Find all missing N-digit values
find_missing = proc (db: string, n: int) returns (sequence[string])
db := db || string$substr(db, 1, n) % wrap
missing: array[string] := array[string]$[]
s: stream := stream$create_output()
for i: int in int$from_to(0, 10**n-1) do
%s: stream := stream$create_output()
stream$reset(s)
stream$putzero(s, int$unparse(i), n)
val: string := stream$get_contents(s)
if string$indexs(val, db) = 0 then
array[string]$addh(missing, val)
end
end
return(sequence[string]$a2s(missing))
end find_missing
% Report all missing values, or 'none'.
validate = proc (s: stream, db: string, n: int)
stream$puts(s, "Validating...")
missing: sequence[string] := find_missing(db, n)
for v: string in sequence[string]$elements(missing) do
stream$puts(s, " " || v)
end
if sequence[string]$size(missing) = 0 then
stream$puts(s, " none")
end
stream$putl(s, " missing.")
end validate
start_up = proc ()
po: stream := stream$primary_output()
% Generate the De Bruijn sequence for 4-digit numbers
db: string := de_bruijn$generate(10, 4)
% Report length and first and last digits
stream$putl(po, "Length: " || int$unparse(string$size(db)))
stream$putl(po, "First 130 characters:")
stream$putl(po, string$substr(db, 1, 130))
stream$putl(po, "Last 130 characters:")
stream$putl(po, string$substr(db, string$size(db)-130, 130))
% See if there are any missing values in the sequence
validate(po, db, 4)
% Reverse and validate again
stream$putl(po, "Reversing...")
validate(po, reverse(db), 4)
% Replace the 4444'th element with '.' and validate again
stream$putl(po, "Setting the 4444'th character to '.'...")
db := string$substr(db, 1, 4443) || "." || string$rest(db, 4445)
validate(po, db, 4)
end start_up
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