How to resolve the algorithm Determine if a string has all the same characters step by step in the Go programming language
How to resolve the algorithm Determine if a string has all the same characters step by step in the Go programming language
Table of Contents
Problem Statement
Given a character string Β (which may be empty, or have a length of zero characters):
Use (at least) these seven test values Β (strings):
Show all output here on this page.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Determine if a string has all the same characters step by step in the Go programming language
Code Overview:
The provided Go program analyzes a series of strings to determine whether all characters in each string are the same. It iterates through each character in a string and checks for differences. If a difference is found, it prints an error message and returns. Otherwise, it prints a success message.
Detailed Explanation:
Package Declaration:
package main
This line declares that the program is in the main
package, indicating that it contains the program's entry point.
Import Statements:
import "fmt"
This line imports the fmt
package, which provides functions for printing formatted text and input.
analyze
Function:
func analyze(s string) {
// ...
}
This function analyzes a string s
to determine whether all of its characters are the same.
-
Convert String to Runes:
chars := []rune(s)
- Converts the strings
into a slice of Unicode code points, represented as runes. -
Get String Length:
le := len(chars)
- Computes the length of the rune slice, which is the same as the length of the original string. -
Print Analysis Introduction:
fmt.Printf("Analyzing %q which has a length of %d:\n", s, le)
- Prints information about the string being analyzed, including its original value and length. -
Iterate over Characters:
for i := 1; i < le; i++
- Iterates over each character in the string, starting from the second character (index 1). -
Compare Characters:
if chars[i] != chars[i-1] { fmt.Println(" Not all characters in the string are the same.") fmt.Printf(" %q (%#[1]x) is different at position %d.\n\n", chars[i], i+1) return }
- Checks if the current character
chars[i]
is different from the previous characterchars[i-1]
. - If they are different, it prints error messages and returns from the function.
fmt.Printf(" %q (%#[1]x) is different at position %d.\n\n", chars[i], i+1)
prints the current character (as a string and as its hexadecimal representation), along with its position in the string.
- Checks if the current character
-
Print Success Message:
fmt.Println(" All characters in the string are the same.\n")
- If the loop completes without finding any differences, it prints a success message indicating that all characters in the string are the same.
main
Function:
func main() {
strings := []string{
// ...
}
for _, s := range strings {
analyze(s)
}
}
-
Define String Slice:
strings := []string{...}
- Defines a slice of strings, each of which will be analyzed by theanalyze
function. -
Iterate over Strings:
for _, s := range strings
- Iterates over each strings
in thestrings
slice. -
Call
analyze
Function:analyze(s)
- Calls theanalyze
function to analyze the current strings
.
Source code in the go programming language
package main
import "fmt"
func analyze(s string) {
chars := []rune(s)
le := len(chars)
fmt.Printf("Analyzing %q which has a length of %d:\n", s, le)
if le > 1 {
for i := 1; i < le; i++ {
if chars[i] != chars[i-1] {
fmt.Println(" Not all characters in the string are the same.")
fmt.Printf(" %q (%#[1]x) is different at position %d.\n\n", chars[i], i+1)
return
}
}
}
fmt.Println(" All characters in the string are the same.\n")
}
func main() {
strings := []string{
"",
" ",
"2",
"333",
".55",
"tttTTT",
"4444 444k",
"pΓ©pΓ©",
"πΆπΆπΊπΆ",
"ππππ",
}
for _, s := range strings {
analyze(s)
}
}
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