How to resolve the algorithm Determine if a string has all the same characters step by step in the OCaml programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Determine if a string has all the same characters step by step in the OCaml programming language
Table of Contents
Problem Statement
Given a character string (which may be empty, or have a length of zero characters):
Use (at least) these seven test values (strings):
Show all output here on this page.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Determine if a string has all the same characters step by step in the OCaml programming language
Source code in the ocaml programming language
(* Task: Determine if a string has all the same characters *)
(* Create a function that determines whether all characters in a string are identical,
or returns the index of first different character.
Using the option type here to combine the functionality.
*)
let str_first_diff_char (s : string) : int option =
let len = String.length s in
if len = 0
then None
else
let first = s.[0] in
let rec helper idx =
if idx >= len
then None
else if s.[idx] = first
then helper (idx + 1)
else Some idx
in
helper 1
;;
(* Task display: using format of Ada
Example:
Input = "333", length = 3
All characters are the same.
Input = ".55", length = 3
First difference at position 2, character = '5', hex = 16#35#
*)
let format_answer s =
let first_line = "Input = \"" ^ s ^ "\", length = " ^ (s |> String.length |> string_of_int) in
let second_line = match str_first_diff_char s with
| None -> " All characters are the same."
| Some idx -> Printf.sprintf " First difference at position %d, character = %C, hex = %#x" (idx+1) s.[idx] (Char.code s.[idx])
in
print_endline first_line; print_endline second_line
;;
let _ =
[""; " "; "2"; "333"; ".55"; "tttTTT"; "4444 444k"]
|> List.iter format_answer
;;
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