How to resolve the algorithm Determine if a string has all unique characters step by step in the Groovy programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Determine if a string has all unique characters step by step in the Groovy programming language
Table of Contents
Problem Statement
Given a character string (which may be empty, or have a length of zero characters):
Use (at least) these five test values (strings):
Show all output here on this page.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Determine if a string has all unique characters step by step in the Groovy programming language
Source code in the groovy programming language
class StringUniqueCharacters {
static void main(String[] args) {
printf("%-40s %2s %10s %8s %s %s%n", "String", "Length", "All Unique", "1st Diff", "Hex", "Positions")
printf("%-40s %2s %10s %8s %s %s%n", "------------------------", "------", "----------", "--------", "---", "---------")
for (String s : ["", ".", "abcABC", "XYZ ZYX", "1234567890ABCDEFGHIJKLMN0PQRSTUVWXYZ"]) {
processString(s)
}
}
private static void processString(String input) {
Map<Character, Integer> charMap = new HashMap<>()
char dup = 0
int index = 0
int pos1 = -1
int pos2 = -1
for (char key : input.toCharArray()) {
index++
if (charMap.containsKey(key)) {
dup = key
pos1 = charMap.get(key)
pos2 = index
break
}
charMap.put(key, index)
}
String unique = (int) dup == 0 ? "yes" : "no"
String diff = (int) dup == 0 ? "" : "'" + dup + "'"
String hex = (int) dup == 0 ? "" : Integer.toHexString((int) dup).toUpperCase()
String position = (int) dup == 0 ? "" : pos1 + " " + pos2
printf("%-40s %-6d %-10s %-8s %-3s %-5s%n", input, input.length(), unique, diff, hex, position)
}
}
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