How to resolve the algorithm Determine if a string has all unique characters step by step in the V (Vlang) programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Determine if a string has all unique characters step by step in the V (Vlang) programming language
Table of Contents
Problem Statement
Given a character string (which may be empty, or have a length of zero characters):
Use (at least) these five test values (strings):
Show all output here on this page.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Determine if a string has all unique characters step by step in the V (Vlang) programming language
Source code in the v programming language
fn analyze(s string) {
chars := s.runes()
le := chars.len
println("Analyzing $s which has a length of $le:")
if le > 1 {
for i := 0; i < le-1; i++ {
for j := i + 1; j < le; j++ {
if chars[j] == chars[i] {
println(" Not all characters in the string are unique.")
println(" '${chars[i]}'' (0x${chars[i]:x}) is duplicated at positions ${i+1} and ${j+1}.\n")
return
}
}
}
}
println(" All characters in the string are unique.\n")
}
fn main() {
strings := [
"",
".",
"abcABC",
"XYZ ZYX",
"1234567890ABCDEFGHIJKLMN0PQRSTUVWXYZ",
"01234567890ABCDEFGHIJKLMN0PQRSTUVWXYZ0X",
"hétérogénéité",
"🎆🎃🎇🎈",
"😍😀🙌💃😍🙌",
"🐠🐟🐡🦈🐬🐳🐋🐡",
]
for s in strings {
analyze(s)
}
}
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