How to resolve the algorithm Determine if only one instance is running step by step in the Ada programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Determine if only one instance is running step by step in the Ada programming language

Table of Contents

Problem Statement

This task is to determine if there is only one instance of an application running. If the program discovers that an instance of it is already running, then it should display a message indicating that it is already running and exit.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Determine if only one instance is running step by step in the Ada programming language

Source code in the ada programming language

with Ada.Text_IO;

procedure Single_Instance is

   package IO renames Ada.Text_IO;
   Lock_File: IO.File_Type;
   Lock_File_Name: String := "single_instance.magic_lock";

begin
   begin
      IO.Open(File => Lock_File, Mode=> IO.In_File, Name => Lock_File_Name);
      IO.Close(Lock_File);
      IO.Put_Line("I can't -- another instance of me is running ...");
   exception
      when IO.Name_Error =>
         IO.Put_Line("I can run!");
         IO.Create(File => Lock_File, Name => Lock_File_Name);
         for I in 1 .. 10 loop
            IO.Put(Integer'Image(I));
            delay 1.0; -- wait one second
         end loop;
         IO.Delete(Lock_File);
         IO.New_Line;
         IO.Put_Line("I am done!");
   end;
exception
   when others => IO.Delete(Lock_File);
end Single_Instance;


  

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