How to resolve the algorithm Determine if only one instance is running step by step in the Ada programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Determine if only one instance is running step by step in the Ada programming language
Table of Contents
Problem Statement
This task is to determine if there is only one instance of an application running. If the program discovers that an instance of it is already running, then it should display a message indicating that it is already running and exit.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Determine if only one instance is running step by step in the Ada programming language
Source code in the ada programming language
with Ada.Text_IO;
procedure Single_Instance is
package IO renames Ada.Text_IO;
Lock_File: IO.File_Type;
Lock_File_Name: String := "single_instance.magic_lock";
begin
begin
IO.Open(File => Lock_File, Mode=> IO.In_File, Name => Lock_File_Name);
IO.Close(Lock_File);
IO.Put_Line("I can't -- another instance of me is running ...");
exception
when IO.Name_Error =>
IO.Put_Line("I can run!");
IO.Create(File => Lock_File, Name => Lock_File_Name);
for I in 1 .. 10 loop
IO.Put(Integer'Image(I));
delay 1.0; -- wait one second
end loop;
IO.Delete(Lock_File);
IO.New_Line;
IO.Put_Line("I am done!");
end;
exception
when others => IO.Delete(Lock_File);
end Single_Instance;
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