How to resolve the algorithm Determine if only one instance is running step by step in the REXX programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Determine if only one instance is running step by step in the REXX programming language

Table of Contents

Problem Statement

This task is to determine if there is only one instance of an application running. If the program discovers that an instance of it is already running, then it should display a message indicating that it is already running and exit.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Determine if only one instance is running step by step in the REXX programming language

Source code in the rexx programming language

/* Simple ARexx program to open a port after checking if it's already open */
IF Show('PORTS','ROSETTA') THEN DO           /* Port is already open; exit */
   SAY 'This program may only be run in a single instance at a time.'
   EXIT 5                                    /* Exit with a mild warning   */
   END
                 /* Open rexxsupport.library so that ports can be opened   */
IF ~Show('LIBRARIES','rexxsupport.library') 
   THEN CALL AddLib('rexxsupport.library',0,-30,0) 

IF ~OpenPort('ROSETTA')    THEN EXIT 10       /* Open port, end if it fails */

SAY 'Program is now running.'

DO FOREVER                                    /* Busyloop                   */
   /* Program stuff here */
   END

EXIT 0


  

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