How to resolve the algorithm Doubly-linked list/Element insertion step by step in the REXX programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Doubly-linked list/Element insertion step by step in the REXX programming language

Table of Contents

Problem Statement

This is much like inserting into a Singly-Linked List, but with added assignments so that the backwards-pointing links remain correct.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Doubly-linked list/Element insertion step by step in the REXX programming language

Source code in the rexx programming language

/*REXX program that implements various   List Manager   functions.      */
/*┌────────────────────────────────────────────────────────────────────┐
┌─┘                    Functions of the  List Manager                  └─┐
│                                                                        │
│ @init      ─── initializes the List.                                   │
│                                                                        │
│ @size      ─── returns the size of the List  [could be  0  (zero)].    │
│                                                                        │
│ @show      ─── shows (displays) the complete List.                     │
│ @show k,1  ─── shows (displays) the  Kth  item.                        │
│ @show k,m  ─── shows (displays)   M  items,  starting with  Kth  item. │
│ @show ,,─1 ─── shows (displays) the complete List backwards.           │
│                                                                        │
│ @get  k    ─── returns the  Kth  item.                                 │
│ @get  k,m  ─── returns the  M  items  starting with the  Kth  item.    │
│                                                                        │
│ @put  x    ─── adds the  X  items to the  end  (tail) of the List.     │
│ @put  x,0  ─── adds the  X  items to the start (head) of the List.     │
│ @put  x,k  ─── adds the  X  items to before of the  Kth  item.         │
│                                                                        │
│ @del  k    ─── deletes the item  K.                                    │
│ @del  k,m  ─── deletes the   M  items  starting with item  K.          │
└─┐                                                                    ┌─┘
  └────────────────────────────────────────────────────────────────────┘*/
call sy 'initializing the list.'           ; call @init
call sy 'building list: Was it a cat I saw'; call @put 'Was it a cat I saw'
call sy 'displaying list size.'            ; say 'list size='@size()
call sy 'forward list'                     ; call @show
call sy 'backward list'                    ; call @show ,,-1
call sy 'showing 4th item'                 ; call @show 4,1
call sy 'showing 6th & 6th items'          ; call @show 5,2
call sy 'adding item before item 4: black' ; call @put 'black',4
call sy 'showing list'                     ; call @show
call sy 'adding to tail: there, in the ...'; call @put 'there, in the shadows, stalking its prey (and next meal).'
call sy 'showing list'                     ; call @show
call sy 'adding to head: Oy!'              ; call @put  'Oy!',0
call sy 'showing list'                     ; call @show
exit                                   /*stick a fork in it, we're done.*/
/*──────────────────────────────────subroutines─────────────────────────*/
p:       return word(arg(1),1)
sy:      say; say left('',30) "───" arg(1) '───'; return
@hasopt: arg o; return pos(o,opt)\==0
@size:   return $.#
@init:   $.@=''; $.#=0; return 0
@adjust: $.@=space($.@); $.#=words($.@); return 0

@parms:  arg opt
         if @hasopt('k') then k=min($.#+1,max(1,p(k 1)))
         if @hasopt('m') then m=p(m 1)
         if @hasopt('d') then dir=p(dir 1)
         return

@show:   procedure expose $.;   parse arg k,m,dir
         if dir==-1 & k=='' then k=$.#
         m=p(m $.#);
         call @parms 'kmd'
         say @get(k,m,dir);
         return 0

@get:    procedure expose $.;   arg k,m,dir,_
         call @parms 'kmd'
                             do j=k for m by dir while j>0 & j<=$.#
                             _=_ subword($.@,j,1)
                             end   /*j*/
         return strip(_)

@put:    procedure expose $.;   parse arg x,k
         k=p(k $.#+1)
         call @parms 'k'
         $.@=subword($.@,1,max(0,k-1)) x subword($.@,k)
         call @adjust
         return 0

@del:    procedure expose $.;   arg k,m
         call @parms 'km'
         _=subword($.@,k,k-1) subword($.@,k+m)
         $.@=_
         call @adjust
         return


  

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