How to resolve the algorithm Enumerations step by step in the Ruby programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Enumerations step by step in the Ruby programming language

Table of Contents

Problem Statement

Create an enumeration of constants with and without explicit values.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Enumerations step by step in the Ruby programming language

The code defines the two modules Fruits and Card containing constants:

Fruits module:

  • Defines constants APPLE, BANANA, and CHERRY with values 0, 1, and 2, respectively.

Card module:

  • SUITS: An array of symbols representing the suits in a deck of cards ([:Clubs, :Hearts, :Spades, :Diamonds]).
  • SUIT_VALUE: A hash created using the each_with_index method to associate each suit with its corresponding index. In Ruby 2.1 and later, this is done with SUITS.each_with_index.to_h. In earlier versions, it would be Hash[SUITS.each_with_index.to_a].
  • PIPS: An array of symbols representing the pips (numbers and face cards) in a deck of cards ([:2, :3, :4, :5, :6, :7, :8, :9, :10, :Jack, :Queen, :King, :Ace]).
  • PIP_VALUE: A hash created using each.with_index(2) to associate each pip with its corresponding value, starting from 2. Ruby 2.1 and later uses PIPS.each.with_index(2).to_h, while earlier versions use Hash[PIPS.each.with_index(2).to_a].

Usage of #include? method with constant symbols:

FRUITS = [:apple, :banana, :cherry]
val = :banana
FRUITS.include?(val)      #=> true

This shows how the include? method can be used to check if a value is present in an array of symbols representing the constants defined in the Fruits module.

Source code in the ruby programming language

module Fruits
  APPLE  = 0
  BANANA = 1
  CHERRY = 2
end

# It is possible to use a symbol if the value is unrelated.

FRUITS = [:apple, :banana, :cherry]
val = :banana
FRUITS.include?(val)      #=> true


module Card
  # constants
  SUITS = %i(Clubs Hearts Spades Diamonds)
  SUIT_VALUE = SUITS.each_with_index.to_h               # version 2.1+
# SUIT_VALUE = Hash[ SUITS.each_with_index.to_a ]       # before it
  #=> {:Clubs=>0, :Hearts=>1, :Spades=>2, :Diamonds=>3}
 
  PIPS = %i(2 3 4 5 6 7 8 9 10 Jack Queen King Ace)
  PIP_VALUE = PIPS.each.with_index(2).to_h              # version 2.1+
# PIP_VALUE = Hash[ PIPS.each.with_index(2).to_a ]      # before it
  #=> {:"2"=>2, :"3"=>3, :"4"=>4, :"5"=>5, :"6"=>6, :"7"=>7, :"8"=>8, :"9"=>9, :"10"=>10, :Jack=>11, :Queen=>12, :King=>13, :Ace=>14}
end


  

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