How to resolve the algorithm Euler's identity step by step in the C# programming language
How to resolve the algorithm Euler's identity step by step in the C# programming language
Table of Contents
Problem Statement
In mathematics, Euler's identity is the equality: where Euler's identity is often cited as an example of deep mathematical beauty. Three of the basic arithmetic operations occur exactly once each: addition, multiplication, and exponentiation. The identity also links five fundamental mathematical constants: Show in your language that Euler's identity is true. As much as possible and practical, mimic the Euler's identity equation. Most languages are limited to IEEE 754 floating point calculations so will have some error in the calculation. If that is the case, or there is some other limitation, show that ei
π
{\displaystyle \pi }
- 1 is approximately equal to zero and show the amount of error in the calculation. If your language is capable of symbolic calculations, show that ei
π
{\displaystyle \pi }
- 1 is exactly equal to zero for bonus kudos points.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Euler's identity step by step in the C# programming language
This code demonstrates the uses of System.Numerics
library for working with complex numbers. Specifically, it evaluates the famous mathematical expression e^(iπ) + 1
-
Complex e = Math.E creates a Complex object representing the mathematical constant e(Euler's number)
-
Complex i = Complex.ImaginaryOne; creates a Complex object representing the imaginary unit i(where i^2 = -1).
-
Complex π = Math.PI: creates a Complex representing the mathematical constant pi(the ratio of a circle's circumference to its diameter)
-
Console.WriteLine(Complex.Pow(e, i * π) + 1);
-
Complex.Pow(e, i * π) calculates e to the power of iπ using the built-in Pow method.
-
+ 1: adds 1 to the result of the exponentiation.
-
This line evaluates the expression
e^(iπ) + 1
and prints the result to the console.
The expected output of this code is 1+0E-20i
which represents the complex number 1 with a very small imaginary component close to zero. This result confirms Euler's identity, which states that e^(iπ) + 1 = 0
.
Source code in the csharp programming language
using System;
using System.Numerics;
public class Program
{
static void Main() {
Complex e = Math.E;
Complex i = Complex.ImaginaryOne;
Complex π = Math.PI;
Console.WriteLine(Complex.Pow(e, i * π) + 1);
}
}
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