Step by Step solution about How to resolve the algorithm Even or odd step by step in the C programming language

In C programming language the & operator returns 1 if the bits in the position of the operator are both 1, and 0 otherwise. Therefore, the expression x & 1 returns the least significant bit of x, which is 1 if x is odd and 0 if x is even.

This trick is commonly used to check if a number is odd or even. For example, in the provided snippet, if x is odd, the expression x & 1 evaluates to 1 and the first branch of the if statement is executed. If x is even, the expression x & 1 evaluates to 0 and the second branch of the if statement is executed.

The second snippet uses the mpz_even_p() and mpz_odd_p() functions from the GNU Multiple Precision Arithmetic Library (GMP) to check if a number is even or odd, respectively. These functions take a mpz_t variable as an argument and return 1 if the number is even or odd, and 0 otherwise.

if (x & 1) {
    /* x is odd */
} else {
    /* or not */
}


mpz_t x;
...
if (mpz_even_p(x)) { /* x is even */ }
if (mpz_odd_p(x))  { /* x is odd */ }