Step by Step solution about How to resolve the algorithm Even or odd step by step in the C++ programming language

The code you provided contains two functions, isOdd and isEven, that check if a given integer is odd or even, respectively. The first two functions, isOdd and isEven, are defined using the modulo operator (%) to check if the number is divisible by 2. If the result of the modulo operation is 0, the number is even; otherwise, it is odd.

The remaining functions are templated functions that check if a given value is odd or even. The isEven function is defined as a constexpr function, which means that it can be evaluated at compile time. The isEven function is defined for the type int and uses the bitwise AND operator (&) to check if the least significant bit of the number is 0. If the least significant bit is 0, the number is even; otherwise, it is odd.

The isOdd function is defined as a constexpr function and uses the ! operator to negate the result of the isEven function. If the isEven function returns true, the isOdd function returns false, and vice versa.

bool isOdd(int x)
{
    return x % 2;
}

bool isEven(int x)
{
    return !(x % 2);
}


template < typename T >
constexpr inline bool isEven( const T& v )
{
    return isEven( int( v ) );
}

template <>
constexpr inline bool isEven< int >( const int& v )
{
    return (v & 1) == 0;
}

template < typename T >
constexpr inline bool isOdd( const T& v )
{
    return !isEven(v);
}