How to resolve the algorithm Exceptions/Catch an exception thrown in a nested call step by step in the AutoHotkey programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Exceptions/Catch an exception thrown in a nested call step by step in the AutoHotkey programming language
Table of Contents
Problem Statement
Show how to create a user-defined exception and show how to catch an exception raised from several nested calls away.
Show/describe what happens when the program is run.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Exceptions/Catch an exception thrown in a nested call step by step in the AutoHotkey programming language
Source code in the autohotkey programming language
global U0 := Exception("First Exception")
global U1 := Exception("Second Exception")
foo()
foo(){
try
bar()
catch e
MsgBox % "An exception was raised: " e.Message
bar()
}
bar(){
baz()
}
baz(){
static calls := 0
if ( ++calls = 1 )
throw U0
else if ( calls = 2 )
throw U1
}
foo()
Return
foo()
{
bar(0)
If InStr(ErrorLevel, "U0")
MsgBox caught error: U0
bar(1)
If InStr(ErrorLevel, "U0")
MsgBox caught error: U0
}
bar(i)
{
StringReplace, ErrorLevel, ErrorLevel, baz_error, , All ; clear baz_error(s)
If !baz(i)
ErrorLevel .= "baz_error" ; add baz_error to errorstack
}
baz(i)
{
StringReplace, ErrorLevel, ErrorLevel, U1, , All ; clear U1 errors
StringReplace, ErrorLevel, ErrorLevel, U0, , All ; clear U0 errors
If i
ErrorLevel .= "U1" ; add U1 errors to errorstack
Else
ErrorLevel .= "U0"
Return 1
}
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