How to resolve the algorithm Exceptions step by step in the Mathematica / Wolfram Language programming language

Published on 22 June 2024 08:30 PM

How to resolve the algorithm Exceptions step by step in the Mathematica / Wolfram Language programming language

Table of Contents

Problem Statement

This task is to give an example of an exception handling routine and to "throw" a new exception.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Exceptions step by step in the Mathematica / Wolfram Language programming language

The Wolfram Language code provided defines a function f that takes a single argument x. The function returns the factorial of x if x is less than or equal to 10, and throws an overflow error if x is greater than 10.

The Throw function is used to raise an error. When an error is raised, it can be caught using the Catch function. The Catch function takes two arguments: the expression to be evaluated, and a list of patterns to match against any errors that are raised.

In the example usage, the Catch function is used to catch the overflow error that is raised when f[11] is evaluated. The + operator is used to add the results of f[2] and f[11]. The -> operator is used to assign the result of the Catch function to the variable result.

The value of result is overflow, which indicates that an error occurred when evaluating f[11].

In the second example usage, the Catch function is used to catch the overflow error that is raised when f[3] is evaluated. The + operator is used to add the results of f[2] and f[3]. The -> operator is used to assign the result of the Catch function to the variable result.

The value of result is 8, which is the factorial of 3.

Source code in the wolfram programming language

f[x_] := If[x > 10, Throw[overflow], x!]

Example usage : 
Catch[f[2] + f[11]]
-> overflow

Catch[f[2] + f[3]]
-> 8


  

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