How to resolve the algorithm Exceptions step by step in the Mathematica / Wolfram Language programming language
How to resolve the algorithm Exceptions step by step in the Mathematica / Wolfram Language programming language
Table of Contents
Problem Statement
This task is to give an example of an exception handling routine and to "throw" a new exception.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Exceptions step by step in the Mathematica / Wolfram Language programming language
The Wolfram Language code provided defines a function f
that takes a single argument x
. The function returns the factorial of x
if x
is less than or equal to 10, and throws an overflow
error if x
is greater than 10.
The Throw
function is used to raise an error. When an error is raised, it can be caught using the Catch
function. The Catch
function takes two arguments: the expression to be evaluated, and a list of patterns to match against any errors that are raised.
In the example usage, the Catch
function is used to catch the overflow
error that is raised when f[11]
is evaluated. The +
operator is used to add the results of f[2]
and f[11]
. The ->
operator is used to assign the result of the Catch
function to the variable result
.
The value of result
is overflow
, which indicates that an error occurred when evaluating f[11]
.
In the second example usage, the Catch
function is used to catch the overflow
error that is raised when f[3]
is evaluated. The +
operator is used to add the results of f[2]
and f[3]
. The ->
operator is used to assign the result of the Catch
function to the variable result
.
The value of result
is 8
, which is the factorial of 3.
Source code in the wolfram programming language
f[x_] := If[x > 10, Throw[overflow], x!]
Example usage :
Catch[f[2] + f[11]]
-> overflow
Catch[f[2] + f[3]]
-> 8
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