How to resolve the algorithm Execute HQ9+ step by step in the Liberty BASIC programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Execute HQ9+ step by step in the Liberty BASIC programming language
Table of Contents
Problem Statement
Implement a HQ9+ interpreter or compiler.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Execute HQ9+ step by step in the Liberty BASIC programming language
Source code in the liberty programming language
'Try this hq9+ program - "hq9+HqQ+Qq"
Prompt "Please input your hq9+ program."; code$
Print hq9plus$(code$)
End
Function hq9plus$(code$)
For i = 1 to Len(code$)
Select Case
Case Upper$(Mid$(code$, i, 1)) = "H"
hq9plus$ = hq9plus$ + "Hello, world!"
Case Upper$(Mid$(code$, i, 1)) = "Q"
hq9plus$ = hq9plus$ + code$
Case Mid$(code$, i, 1) = "9"
For bottles = 99 To 1 Step -1
hq9plus$ = hq9plus$ + str$(bottles) + " bottle"
If (bottles > 1) Then hq9plus$ = hq9plus$ + "s"
hq9plus$ = hq9plus$ + " of beer on the wall, " + str$(bottles) + " bottle"
If (bottles > 1) Then hq9plus$ = hq9plus$ + "s"
hq9plus$ = hq9plus$ + " of beer," + chr$(13) + chr$(10) + "Take one down, pass it around, " + str$(bottles - 1) + " bottle"
If (bottles > 2) Or (bottles = 1) Then hq9plus$ = hq9plus$ + "s"
hq9plus$ = hq9plus$ + " of beer on the wall." + chr$(13) + chr$(10)
Next bottles
hq9plus$ = hq9plus$ + "No more bottles of beer on the wall, no more bottles of beer." _
+ chr$(13) + chr$(10) + "Go to the store and buy some more, 99 bottles of beer on the wall."
Case Mid$(code$, i, 1) = "+"
accumulator = (accumulator + 1)
End Select
If Mid$(code$, i, 1) <> "+" Then
hq9plus$ = hq9plus$ + chr$(13) + chr$(10)
End If
Next i
hq9plus$ = Left$(hq9plus$, (Len(hq9plus$) - 2))
End Function
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