How to resolve the algorithm Exponentiation operator step by step in the Lua programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Exponentiation operator step by step in the Lua programming language
Table of Contents
Problem Statement
Most programming languages have a built-in implementation of exponentiation.
Re-implement integer exponentiation for both intint and floatint as both a procedure, and an operator (if your language supports operator definition). If the language supports operator (or procedure) overloading, then an overloaded form should be provided for both intint and floatint variants.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Exponentiation operator step by step in the Lua programming language
Source code in the lua programming language
number = {}
function number.pow( a, b )
local ret = 1
if b >= 0 then
for i = 1, b do
ret = ret * a.val
end
else
for i = b, -1 do
ret = ret / a.val
end
end
return ret
end
function number.New( v )
local num = { val = v }
local mt = { __pow = number.pow }
setmetatable( num, mt )
return num
end
x = number.New( 5 )
print( x^2 ) --> 25
print( number.pow( x, -4 ) ) --> 0.016
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