How to resolve the algorithm Exponentiation order step by step in the C programming language

Published on 7 June 2024 03:52 AM
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How to resolve the algorithm Exponentiation order step by step in the C programming language

Table of Contents

Problem Statement

This task will demonstrate the order of exponentiation   (xy)   when there are multiple exponents. (Many programming languages,   especially those with extended─precision integer arithmetic,   usually support one of **, ^, ↑ or some such for exponentiation.)

Show the result of a language's evaluation of multiple exponentiation (either as an integer or floating point). If your language's exponentiation operator is not one of the usual ones, please comment on how to recognize it.

Using whatever operator or syntax your language supports (if any), show the results in three lines (with identification):

If there are other methods (or formats) of multiple exponentiations, show them as well.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Exponentiation order step by step in the C programming language

The provided C code demonstrates the use of the pow() function from the math.h library to calculate exponential operations:

  1. Header Files:

    • The code includes the necessary header files:
      • <stdio.h> for input and output operations.
      • <math.h> for mathematical functions, specifically the pow() function.
  2. main() Function:

    • This is the entry point of the program.
  3. Exponential Calculations:

    • The program performs two calculations using the pow() function:
      • First Calculation:
        printf("(5 ^ 3) ^ 2 = %.0f", pow(pow(5, 3), 2));
        • This line calculates the value of (5^3)^2. It first raises 5 to the power of 3 (5^3 = 125) and then raises that result to the power of 2 ((5^3)^2 = 15625). The result is printed as an integer with no decimal places.
      • Second Calculation:
        printf("\n5 ^ (3 ^ 2) = %.0f", pow(5, pow(3, 2)));
        • This line calculates the value of 5^(3^2). It first raises 3 to the power of 2 (3^2 = 9) and then raises 5 to that power (5^(3^2) = 1953125). The result is again printed as an integer.
  4. Output:

    • The program prints the results of both calculations:
      • (5 ^ 3) ^ 2 = 15625
      • 5 ^ (3 ^ 2) = 1953125

Source code in the c programming language

#include<stdio.h>
#include<math.h>

int main()
{
    printf("(5 ^ 3) ^ 2 = %.0f",pow(pow(5,3),2));
    printf("\n5 ^ (3 ^ 2) = %.0f",pow(5,pow(3,2)));
	
    return 0;
}


  

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