How to resolve the algorithm Exponentiation order step by step in the Rust programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Exponentiation order step by step in the Rust programming language
Table of Contents
Problem Statement
This task will demonstrate the order of exponentiation (xy) when there are multiple exponents. (Many programming languages, especially those with extended─precision integer arithmetic, usually support one of **, ^, ↑ or some such for exponentiation.)
Show the result of a language's evaluation of multiple exponentiation (either as an integer or floating point). If your language's exponentiation operator is not one of the usual ones, please comment on how to recognize it.
Using whatever operator or syntax your language supports (if any), show the results in three lines (with identification):
If there are other methods (or formats) of multiple exponentiations, show them as well.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Exponentiation order step by step in the Rust programming language
Source code in the rust programming language
fn main() {
println!("5**3**2 = {:7}", 5u32.pow(3).pow(2));
println!("(5**3)**2 = {:7}", (5u32.pow(3)).pow(2));
println!("5**(3**2) = {:7}", 5u32.pow(3u32.pow(2)));
}
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