How to resolve the algorithm Find the intersection of two lines step by step in the Julia programming language

Published on 22 June 2024 08:30 PM

How to resolve the algorithm Find the intersection of two lines step by step in the Julia programming language

Table of Contents

Problem Statement

Find the point of intersection of two lines in 2D.

The 1st line passes though   (4,0)   and   (6,10) . The 2nd line passes though   (0,3)   and   (10,7) .

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Find the intersection of two lines step by step in the Julia programming language

This Julia code defines custom struct types, Point and Line, to represent and manipulate geometric points and lines, respectively. It also implements a function, intersection, to find the intersection point of two lines. Here's a detailed breakdown:

  1. Struct Definitions:

    • Point{T}: Defines a generic point struct with two fields, x and y, which can hold values of type T. This struct represents a point in a 2D plane.
    • Line{T}: Defines a generic line struct with two fields, s and e, which represent the starting and ending points of the line. The line is defined by these two points. Here, T is a subtype of Real, which includes numeric types like Float64.
  2. intersection Function:

    • This function takes two Line structs, l1 and l2, as input and returns the intersection point of these two lines. It uses the following steps to calculate the intersection:
      • Computes the line equations: a1x + b1y = c1 for l1 and a2x + b2y = c2 for l2, where a1, b1, c1, a2, b2, and c2 are constants.
      • Calculates the determinant Δ = a1 * b2 - a2 * b1. If Δ is zero, the lines are parallel and have no intersection point.
      • Calculates the intersection point coordinates using x = (b2 * c1 - b1 * c2) / Δ and y = (a1 * c2 - a2 * c1) / Δ.
    • The function returns a Point struct representing the intersection point.
  3. Usage Examples:

    • The code demonstrates the usage of the Point and Line structs and the intersection function. It defines two pairs of lines (l1, l2) and calculates their intersection points.
    • The first pair of lines intersect, and the intersection point is printed.
    • The second pair of lines do not intersect, but the code still prints the intersection to show that the computed point is at infinity (due to parallel lines).
  4. GeometryTypes Module:

    • The code briefly showcases the GeometryTypes module, which provides additional geometric constructs and functionality. It defines a LineSegment type and demonstrates the intersects function to check for intersection between two line segments.

Source code in the julia programming language

struct Point{T}
    x::T
    y::T
end

struct Line{T}
    s::Point{T}
    e::Point{T}
end

function intersection(l1::Line{T}, l2::Line{T}) where T<:Real
    a1 = l1.e.y - l1.s.y
    b1 = l1.s.x - l1.e.x
    c1 = a1 * l1.s.x + b1 * l1.s.y

    a2 = l2.e.y - l2.s.y
    b2 = l2.s.x - l2.e.x
    c2 = a2 * l2.s.x + b2 * l2.s.y

    Δ = a1 * b2 - a2 * b1
    # If lines are parallel, intersection point will contain infinite values
    return Point((b2 * c1 - b1 * c2) / Δ, (a1 * c2 - a2 * c1) / Δ)
end

l1 = Line(Point{Float64}(4, 0), Point{Float64}(6, 10))
l2 = Line(Point{Float64}(0, 3), Point{Float64}(10, 7))
println(intersection(l1, l2))

l1 = Line(Point{Float64}(0, 0), Point{Float64}(1, 1))
l2 = Line(Point{Float64}(1, 2), Point{Float64}(4, 5))
println(intersection(l1, l2))


using GeometryTypes

a = LineSegment(Point2f0(4, 0), Point2f0(6, 10))
b = LineSegment(Point2f0(0, 3), Point2f0(10, 7))
@show intersects(a, b)   # --> intersects(a, b) = (true, Float32[5.0, 5.0])


  

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