How to resolve the algorithm Find the intersection of two lines step by step in the Julia programming language
Published on 22 June 2024 08:30 PM
How to resolve the algorithm Find the intersection of two lines step by step in the Julia programming language
Table of Contents
Problem Statement
Find the point of intersection of two lines in 2D.
The 1st line passes though (4,0) and (6,10) . The 2nd line passes though (0,3) and (10,7) .
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Find the intersection of two lines step by step in the Julia programming language
This Julia code defines custom struct types, Point
and Line
, to represent and manipulate geometric points and lines, respectively. It also implements a function, intersection
, to find the intersection point of two lines. Here's a detailed breakdown:
-
Struct Definitions:
Point{T}
: Defines a generic point struct with two fields,x
andy
, which can hold values of typeT
. This struct represents a point in a 2D plane.Line{T}
: Defines a generic line struct with two fields,s
ande
, which represent the starting and ending points of the line. The line is defined by these two points. Here,T
is a subtype ofReal
, which includes numeric types likeFloat64
.
-
intersection
Function:- This function takes two
Line
structs,l1
andl2
, as input and returns the intersection point of these two lines. It uses the following steps to calculate the intersection:- Computes the line equations:
a1x + b1y = c1
forl1
anda2x + b2y = c2
forl2
, wherea1
,b1
,c1
,a2
,b2
, andc2
are constants. - Calculates the determinant
Δ = a1 * b2 - a2 * b1
. IfΔ
is zero, the lines are parallel and have no intersection point. - Calculates the intersection point coordinates using
x = (b2 * c1 - b1 * c2) / Δ
andy = (a1 * c2 - a2 * c1) / Δ
.
- Computes the line equations:
- The function returns a
Point
struct representing the intersection point.
- This function takes two
-
Usage Examples:
- The code demonstrates the usage of the
Point
andLine
structs and theintersection
function. It defines two pairs of lines(l1, l2)
and calculates their intersection points. - The first pair of lines intersect, and the intersection point is printed.
- The second pair of lines do not intersect, but the code still prints the
intersection
to show that the computed point is at infinity (due to parallel lines).
- The code demonstrates the usage of the
-
GeometryTypes
Module:- The code briefly showcases the
GeometryTypes
module, which provides additional geometric constructs and functionality. It defines aLineSegment
type and demonstrates theintersects
function to check for intersection between two line segments.
- The code briefly showcases the
Source code in the julia programming language
struct Point{T}
x::T
y::T
end
struct Line{T}
s::Point{T}
e::Point{T}
end
function intersection(l1::Line{T}, l2::Line{T}) where T<:Real
a1 = l1.e.y - l1.s.y
b1 = l1.s.x - l1.e.x
c1 = a1 * l1.s.x + b1 * l1.s.y
a2 = l2.e.y - l2.s.y
b2 = l2.s.x - l2.e.x
c2 = a2 * l2.s.x + b2 * l2.s.y
Δ = a1 * b2 - a2 * b1
# If lines are parallel, intersection point will contain infinite values
return Point((b2 * c1 - b1 * c2) / Δ, (a1 * c2 - a2 * c1) / Δ)
end
l1 = Line(Point{Float64}(4, 0), Point{Float64}(6, 10))
l2 = Line(Point{Float64}(0, 3), Point{Float64}(10, 7))
println(intersection(l1, l2))
l1 = Line(Point{Float64}(0, 0), Point{Float64}(1, 1))
l2 = Line(Point{Float64}(1, 2), Point{Float64}(4, 5))
println(intersection(l1, l2))
using GeometryTypes
a = LineSegment(Point2f0(4, 0), Point2f0(6, 10))
b = LineSegment(Point2f0(0, 3), Point2f0(10, 7))
@show intersects(a, b) # --> intersects(a, b) = (true, Float32[5.0, 5.0])
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