How to resolve the algorithm First perfect square in base n with n unique digits step by step in the C programming language
How to resolve the algorithm First perfect square in base n with n unique digits step by step in the C programming language
Table of Contents
Problem Statement
Find the first perfect square in a given base N that has at least N digits and exactly N significant unique digits when expressed in base N. E.G. In base 10, the first perfect square with at least 10 unique digits is 1026753849 (32043²). You may use analytical methods to reduce the search space, but the code must do a search. Do not use magic numbers or just feed the code the answer to verify it is correct.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm First perfect square in base n with n unique digits step by step in the C programming language
The provided C code is designed to find and display pairs of numbers (n, s) where s is the square of n and both n and s are expressed in a specific base. The code uses the following functions:
toBaseN(buffer, num, base)
: Converts a long long integernum
to its representation in basebase
and stores the result in the character arraybuffer
.countUnique(inBuf)
: Counts the number of unique characters in the character arrayinBuf
.find(base)
: Finds a pair (n, s) wheres = n^2
and bothn
ands
have unique digits in the givenbase
.
The main()
function calls the find
function for each base from 2 to 15, and for each base, it finds and prints a pair (n, s) that meets the specified criteria.
Here's a step-by-step explanation of the code:
-
The
toBaseN
function converts a long long integernum
to its basebase
representation and stores the result in the character arraybuffer
. -
The
countUnique
function counts the number of unique characters in the character arrayinBuf
. This function is used to check if bothn
ands
have unique digits in a given base. -
The
find
function does the following:- It iterates through positive integers
n
starting from 2. - For each
n
, it calculatess = n^2
. - It converts both
n
ands
to their basebase
representation using thetoBaseN
function. - It checks if the length of the base
base
representation ofs
is at leastbase
and ifs
has unique digits (using thecountUnique
function). - If the conditions are met, it prints the pair (n, s) in the specified format.
- It iterates through positive integers
-
The
main
function iterates through bases from 2 to 15 and calls thefind
function for each base.
Overall, this code demonstrates the use of base conversion and digit uniqueness checks to find pairs of numbers (n, s) where s = n^2
and both n
and s
have unique digits in a given base.
Source code in the c programming language
#include <stdio.h>
#include <string.h>
#define BUFF_SIZE 32
void toBaseN(char buffer[], long long num, int base) {
char *ptr = buffer;
char *tmp;
// write it backwards
while (num >= 1) {
int rem = num % base;
num /= base;
*ptr++ = "0123456789ABCDEF"[rem];
}
*ptr-- = 0;
// now reverse it to be written forwards
for (tmp = buffer; tmp < ptr; tmp++, ptr--) {
char c = *tmp;
*tmp = *ptr;
*ptr = c;
}
}
int countUnique(char inBuf[]) {
char buffer[BUFF_SIZE];
int count = 0;
int pos, nxt;
strcpy_s(buffer, BUFF_SIZE, inBuf);
for (pos = 0; buffer[pos] != 0; pos++) {
if (buffer[pos] != 1) {
count++;
for (nxt = pos + 1; buffer[nxt] != 0; nxt++) {
if (buffer[nxt] == buffer[pos]) {
buffer[nxt] = 1;
}
}
}
}
return count;
}
void find(int base) {
char nBuf[BUFF_SIZE];
char sqBuf[BUFF_SIZE];
long long n, s;
for (n = 2; /*blank*/; n++) {
s = n * n;
toBaseN(sqBuf, s, base);
if (strlen(sqBuf) >= base && countUnique(sqBuf) == base) {
toBaseN(nBuf, n, base);
toBaseN(sqBuf, s, base);
//printf("Base %d : Num %lld Square %lld\n", base, n, s);
printf("Base %d : Num %8s Square %16s\n", base, nBuf, sqBuf);
break;
}
}
}
int main() {
int i;
for (i = 2; i <= 15; i++) {
find(i);
}
return 0;
}
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