How to resolve the algorithm First perfect square in base n with n unique digits step by step in the F# programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm First perfect square in base n with n unique digits step by step in the F# programming language

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Problem Statement

Find the first perfect square in a given base N that has at least N digits and exactly N significant unique digits when expressed in base N. E.G. In base 10, the first perfect square with at least 10 unique digits is 1026753849 (32043²). You may use analytical methods to reduce the search space, but the code must do a search. Do not use magic numbers or just feed the code the answer to verify it is correct.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm First perfect square in base n with n unique digits step by step in the F# programming language

Source code in the fsharp programming language

// Nigel Galloway: May 21st., 2019
let fN g=let g=int64(sqrt(float(pown g (int(g-1L)))))+1L in (Seq.unfold(fun(n,g)->Some(n,(n+g,g+2L))))(g*g,g*2L+1L)
let fG n g=Array.unfold(fun n->if n=0L then None else let n,g=System.Math.DivRem(n,g) in Some(g,n)) n
let fL g=let n=set[0L..g-1L] in Seq.find(fun x->set(fG x g)=n) (fN g)
let toS n g=let a=Array.concat [[|'0'..'9'|];[|'a'..'f'|]] in System.String(Array.rev(fG n g)|>Array.map(fun n->a.[(int n)]))
[2L..16L]|>List.iter(fun n->let g=fL n in printfn "Base %d: %s² -> %s" n (toS (int64(sqrt(float g))) n) (toS g n))


// Nigel Galloway: May 30th., 2019
let fN n g=let g=n|>Array.rev|>Array.mapi(fun i n->(int64 n)*(pown g i))|>Array.sum
           let n=int64(sqrt (float g)) in g=(n*n)
let fG g=lN([|yield 1; yield! Array.zeroCreate(g-2)|])|>Seq.map(fun n->lN2p n [|0..(g-1)|]) |> Seq.filter(fun n->fN n (int64 g))
printfn "%A" (fG 12|>Seq.head) // -> [|1; 2; 4; 10; 7; 11; 5; 3; 8; 6; 0; 9|]
printfn "%A" (fG 14|>Seq.head) // -> [|1; 0; 2; 6; 9; 11; 8; 12; 5; 7; 13; 3; 10; 4|]


  

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