How to resolve the algorithm Four bit adder step by step in the C programming language
How to resolve the algorithm Four bit adder step by step in the C programming language
Table of Contents
Problem Statement
"Simulate" a four-bit adder. This design can be realized using four 1-bit full adders. Each of these 1-bit full adders can be built with two half adders and an or gate. ; Finally a half adder can be made using an xor gate and an and gate. The xor gate can be made using two nots, two ands and one or. Not, or and and, the only allowed "gates" for the task, can be "imitated" by using the bitwise operators of your language. If there is not a bit type in your language, to be sure that the not does not "invert" all the other bits of the basic type (e.g. a byte) we are not interested in, you can use an extra nand (and then not) with the constant 1 on one input. Instead of optimizing and reducing the number of gates used for the final 4-bit adder, build it in the most straightforward way, connecting the other "constructive blocks", in turn made of "simpler" and "smaller" ones.
Solutions should try to be as descriptive as possible, making it as easy as possible to identify "connections" between higher-order "blocks". It is not mandatory to replicate the syntax of higher-order blocks in the atomic "gate" blocks, i.e. basic "gate" operations can be performed as usual bitwise operations, or they can be "wrapped" in a block in order to expose the same syntax of higher-order blocks, at implementers' choice. To test the implementation, show the sum of two four-bit numbers (in binary).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Four bit adder step by step in the C programming language
This C code implements a 4-bit full adder, a digital circuit that performs addition of two 4-bit binary numbers. It includes functions for a half adder (adds two bits) and a full adder (adds three bits) and the main function that tests the 4-bit adder. Here's a detailed breakdown:
-
Custom Data Type and Macros:
typedef char pin_t;
: Defines a custom data typepin_t
to represent a single bit or "pin."- Macros like
IN
andOUT
are used to indicate input and output pins, respectively. PIN(X)
is a macro to define a pin namedX
asstatic
.
-
Half Adder (Function
halfadder
):- Takes two input pins
a
andb
and outputs two pinss
(sum) andc
(carry). - Uses the XOR gate (
XOR(V(a), V(b))
) to calculate the sum and the AND gate (V(a) & V(b)
) to calculate the carry.
- Takes two input pins
-
Full Adder (Function
fulladder
):- Takes three input pins
a
,b
, andic
(carry-in) and outputs two pinss
(sum) andoc
(carry-out). - Internally, it uses two
halfadder
functions to calculate the sum and carry. - The carry-out is calculated as
V(tc) | V(pc)
, wheretc
is the carry from the first half adder, andpc
is the carry from the second half adder.
- Takes three input pins
-
4-Bit Adder (Function
fourbitsadder
):- Takes four input bits for each operand (a and b) and four output bits for the sum (o).
- It uses three
fulladder
functions to calculate the sum and carry for each bit position.
-
Main Function:
- Initializes input and output pins for the 4-bit addition.
- Sets input values for testing:
a = 0001
andb = 0111
. - Calls the
fourbitsadder
function to perform the addition. - Prints the input values, sum, and overflow flag.
In summary, this code simulates a 4-bit binary adder using functions that implement half and full adders. It takes two 4-bit binary numbers as input and outputs their sum and an overflow flag.
Source code in the c programming language
#include <stdio.h>
typedef char pin_t;
#define IN const pin_t *
#define OUT pin_t *
#define PIN(X) pin_t _##X; pin_t *X = & _##X;
#define V(X) (*(X))
/* a NOT that does not soil the rest of the host of the single bit */
#define NOT(X) (~(X)&1)
/* a shortcut to "implement" a XOR using only NOT, AND and OR gates, as
task requirements constrain */
#define XOR(X,Y) ((NOT(X)&(Y)) | ((X)&NOT(Y)))
void halfadder(IN a, IN b, OUT s, OUT c)
{
V(s) = XOR(V(a), V(b));
V(c) = V(a) & V(b);
}
void fulladder(IN a, IN b, IN ic, OUT s, OUT oc)
{
PIN(ps); PIN(pc); PIN(tc);
halfadder(/*INPUT*/a, b, /*OUTPUT*/ps, pc);
halfadder(/*INPUT*/ps, ic, /*OUTPUT*/s, tc);
V(oc) = V(tc) | V(pc);
}
void fourbitsadder(IN a0, IN a1, IN a2, IN a3,
IN b0, IN b1, IN b2, IN b3,
OUT o0, OUT o1, OUT o2, OUT o3,
OUT overflow)
{
PIN(zero); V(zero) = 0;
PIN(tc0); PIN(tc1); PIN(tc2);
fulladder(/*INPUT*/a0, b0, zero, /*OUTPUT*/o0, tc0);
fulladder(/*INPUT*/a1, b1, tc0, /*OUTPUT*/o1, tc1);
fulladder(/*INPUT*/a2, b2, tc1, /*OUTPUT*/o2, tc2);
fulladder(/*INPUT*/a3, b3, tc2, /*OUTPUT*/o3, overflow);
}
int main()
{
PIN(a0); PIN(a1); PIN(a2); PIN(a3);
PIN(b0); PIN(b1); PIN(b2); PIN(b3);
PIN(s0); PIN(s1); PIN(s2); PIN(s3);
PIN(overflow);
V(a3) = 0; V(b3) = 1;
V(a2) = 0; V(b2) = 1;
V(a1) = 1; V(b1) = 1;
V(a0) = 0; V(b0) = 0;
fourbitsadder(a0, a1, a2, a3, /* INPUT */
b0, b1, b2, b3,
s0, s1, s2, s3, /* OUTPUT */
overflow);
printf("%d%d%d%d + %d%d%d%d = %d%d%d%d, overflow = %d\n",
V(a3), V(a2), V(a1), V(a0),
V(b3), V(b2), V(b1), V(b0),
V(s3), V(s2), V(s1), V(s0),
V(overflow));
return 0;
}
You may also check:How to resolve the algorithm Strong and weak primes step by step in the C# programming language
You may also check:How to resolve the algorithm Literals/Floating point step by step in the NetRexx programming language
You may also check:How to resolve the algorithm Comments step by step in the Dragon programming language
You may also check:How to resolve the algorithm Faulhaber's triangle step by step in the jq programming language
You may also check:How to resolve the algorithm String prepend step by step in the XPL0 programming language