How to resolve the algorithm Gapful numbers step by step in the Julia programming language
How to resolve the algorithm Gapful numbers step by step in the Julia programming language
Table of Contents
Problem Statement
Numbers (positive integers expressed in base ten) that are (evenly) divisible by the number formed by the first and last digit are known as gapful numbers.
Evenly divisible means divisible with no remainder.
All one─ and two─digit numbers have this property and are trivially excluded. Only numbers ≥ 100 will be considered for this Rosetta Code task.
187 is a gapful number because it is evenly divisible by the number 17 which is formed by the first and last decimal digits of 187.
About 7.46% of positive integers are gapful.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Gapful numbers step by step in the Julia programming language
The provided Julia code is designed to identify and display gapful numbers. A gapful number is a positive integer whose digits, when split into two groups, form a pair of numbers that divide the original number evenly.
Here's a breakdown of the code:
-
Importing Libraries:
Lazy
is a Julia library that provides lazy sequences, which are sequences that are evaluated only when needed.Formatting
is used for formatting output, such as adding commas to numbers.
-
Defining Helper Functions:
firstlast(a)
: This function takes an arraya
and returns a new integer formed by concatenating the last digit ofa
followed by the first digit ofa
. For example,firstlast([1, 2, 3])
would return 31.isgapful(n)
: This function checks if the numbern
is gapful. It first convertsn
to an array of digits usingdigits(n)
. If the number of digits inn
is less than 3, it returnsfalse
because it's not possible to form a gapful number with fewer than three digits. Otherwise, it calculatesm
using thefirstlast
function and checks ifn
is divisible bym
. If it is, thenn
is gapful, and the function returnstrue
.
-
Generating Gapful Numbers:
gapfuls(start)
: This function returns a lazy sequence of gapful numbers starting from the specifiedstart
value. It uses theLazy.range(start)
function to generate a sequence of integers starting fromstart
, and then filters this sequence using thefilter
function to keep only the gapful numbers as determined by theisgapful
function.
-
Displaying Results:
- The code uses a
for
loop to generate and display the firstn
gapful numbers starting atstart
values of 100, 1,000,000, and 1,000,000,000. - For each
(x, n)
pair, the code prints a message indicating the starting point and the number of gapful numbers to be displayed. - It then uses the
take
function to take the firstn
elements from thegapfuls(x)
sequence and prints them as a comma-separated list.
- The code uses a
In summary, this Julia code defines functions to identify gapful numbers and uses lazy sequences to efficiently generate and display the first specified number of gapful numbers starting from a given starting point.
Source code in the julia programming language
using Lazy, Formatting
firstlast(a) = 10 * a[end] + a[1]
isgapful(n) = (d = digits(n); length(d) < 3 || (m = firstlast(d)) != 0 && mod(n, m) == 0)
gapfuls(start) = filter(isgapful, Lazy.range(start))
for (x, n) in [(100, 30), (1_000_000, 15), (1_000_000_000, 10)]
println("First $n gapful numbers starting at ", format(x, commas=true), ":\n",
take(n, gapfuls(x)))
end
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