How to resolve the algorithm Generator/Exponential step by step in the Erlang programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Generator/Exponential step by step in the Erlang programming language

Table of Contents

Problem Statement

A generator is an executable entity (like a function or procedure) that contains code that yields a sequence of values, one at a time, so that each time you call the generator, the next value in the sequence is provided. Generators are often built on top of coroutines or objects so that the internal state of the object is handled “naturally”. Generators are often used in situations where a sequence is potentially infinite, and where it is possible to construct the next value of the sequence with only minimal state.

Note that this task requires the use of generators in the calculation of the result.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Generator/Exponential step by step in the Erlang programming language

Source code in the erlang programming language

-module( generator ).

-export( [filter/2, next/1, power/1, task/0] ).

filter(	Source_pid, Remove_pid ) ->
	First_remove = next( Remove_pid	),
        erlang:spawn( fun() -> filter_loop(Source_pid, Remove_pid, First_remove) end ).

next( Pid ) ->
    Pid ! {next, erlang:self()},
    receive X -> X end.

power( M ) -> erlang:spawn( fun() -> power_loop(M, 0) end ).

task() ->
    Squares_pid = power( 2 ),
    Cubes_pid = power( 3 ),
    Filter_pid = filter( Squares_pid, Cubes_pid ),
    [next(Filter_pid) || _X <- lists:seq(1, 20)],
    [next(Filter_pid) || _X <- lists:seq(1, 10)].


filter_loop( Pid1, Pid2, N2 ) ->
        receive
        {next, Pid} ->
	       {N, New_N2} = filter_loop_next( next(Pid1), N2, Pid1, Pid2 ),
               Pid ! N
        end,
        filter_loop( Pid1, Pid2, New_N2 ).

filter_loop_next( N1, N2, Pid1, Pid2 ) when N1 > N2 -> filter_loop_next( N1, next(Pid2), Pid1, Pid2 );
filter_loop_next( N, N, Pid1, Pid2 ) -> filter_loop_next( next(Pid1), next(Pid2), Pid1, Pid2 );
filter_loop_next( N1, N2, _Pid1, _Pid2 ) -> {N1, N2}.

power_loop( M, N ) ->
        receive	{next, Pid} -> Pid ! erlang:round(math:pow(N, M) ) end,
	power_loop( M, N + 1 ).


  

You may also check:How to resolve the algorithm Rename a file step by step in the Sidef programming language
You may also check:How to resolve the algorithm Determine if a string is numeric step by step in the E programming language
You may also check:How to resolve the algorithm Array length step by step in the Dyalect programming language
You may also check:How to resolve the algorithm AVL tree step by step in the Go programming language
You may also check:How to resolve the algorithm Hickerson series of almost integers step by step in the D programming language