How to resolve the algorithm Handle a signal step by step in the Go programming language
How to resolve the algorithm Handle a signal step by step in the Go programming language
Table of Contents
Problem Statement
Most operating systems provide interrupt facilities, sometimes called signals either generated by the user or as a result of program failure or reaching a limit like file space. Unhandled signals generally terminate a program in a disorderly manner. Signal handlers are created so that the program behaves in a well-defined manner upon receipt of a signal. Provide a program that displays an integer on each line of output at the rate of about one per half second. Upon receipt of the SIGINT signal (often generated by the user typing ctrl-C ( or better yet, SIGQUIT ctrl-\ )) the program will cease outputting integers, output the number of seconds the program has run, and then the program will quit.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Handle a signal step by step in the Go programming language
The provided Go program demonstrates the use of channels and the select
statement to handle multiple events concurrently. Here's a breakdown of what the code does:
-
package main
: This line specifies that the code is part of the main package. -
import
statements: The program imports several standard packages:"fmt"
for input and output operations"os"
for operating system-related functions"os/signal"
for handling operating system signals"time"
for working with time and durations
-
func main()
: This function is the entry point of the program. -
start := time.Now()
: It records the current time to calculate how long the program runs. -
k := time.Tick(time.Second / 2)
: It creates a channel calledk
that emits a value every half-second using thetime.Tick
function. This channel is for printing numbers at regular intervals. -
sc := make(chan os.Signal, 1)
: It creates a channel calledsc
that can hold one signal. This channel will be used to listen for the interrupt signal (Ctrl+C) from the user. -
signal.Notify(sc, os.Interrupt)
: This line registers to receive the interrupt signal on thesc
channel. When the user presses Ctrl+C, an interrupt signal is sent to the program, and it will be received on this channel. -
for n := 1; ;
: It starts an infinite loop using afor
loop with no condition. This loop continues until the program terminates. -
select
: Inside the loop, there's aselect
statement, which allows the program to block until one of the channels (k
orsc
) becomes ready for reading:case <-k:
: If thek
channel is ready, it receives a value, which effectively prints a number. The numbern
is incremented for each value received.case <-sc:
: If thesc
channel is ready, it receives a value, which indicates that the interrupt signal was triggered. In this case, the program prints the elapsed time and exits.
-
fmt.Println(n)
: After receiving a value from thek
channel, the program prints the numbern
. -
fmt.Printf("Ran for %f seconds.\n", time.Now().Sub(start).Seconds())
: After receiving a value from thesc
channel, the program calculates the elapsed time since it started and prints it.
Overall, the program sets up two channels, one for printing numbers at regular intervals and the other for listening to the interrupt signal. The select
statement allows the program to efficiently handle both events without continuously checking for channel readiness, making the code more efficient and responsive.
Source code in the go programming language
package main
import (
"fmt"
"os"
"os/signal"
"time"
)
func main() {
start := time.Now()
k := time.Tick(time.Second / 2)
sc := make(chan os.Signal, 1)
signal.Notify(sc, os.Interrupt)
for n := 1; ; {
// not busy waiting, this blocks until one of the two
// channel operations is possible
select {
case <-k:
fmt.Println(n)
n++
case <-sc:
fmt.Printf("Ran for %f seconds.\n",
time.Now().Sub(start).Seconds())
return
}
}
}
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