How to resolve the algorithm I before E except after C step by step in the Elixir programming language
How to resolve the algorithm I before E except after C step by step in the Elixir programming language
Table of Contents
Problem Statement
The phrase "I before E, except after C" is a widely known mnemonic which is supposed to help when spelling English words.
Using the word list from http://wiki.puzzlers.org/pub/wordlists/unixdict.txt, check if the two sub-clauses of the phrase are plausible individually:
If both sub-phrases are plausible then the original phrase can be said to be plausible. Something is plausible if the number of words having the feature is more than two times the number of words having the opposite feature (where feature is 'ie' or 'ei' preceded or not by 'c' as appropriate).
As a stretch goal use the entries from the table of Word Frequencies in Written and Spoken English: based on the British National Corpus, (selecting those rows with three space or tab separated words only), to see if the phrase is plausible when word frequencies are taken into account.
Show your output here as well as your program.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm I before E except after C step by step in the Elixir programming language
Source code in the elixir programming language
defmodule RC do
def task(path) do
plausibility_ratio = 2
rules = [ {"I before E when not preceded by C:", "ie", "ei"},
{"E before I when preceded by C:", "cei", "cie"} ]
regex = ~r/ie|ei|cie|cei/
counter = File.read!(path) |> countup(regex)
Enum.all?(rules, fn {str, x, y} ->
nx = counter[x]
ny = counter[y]
ratio = nx / ny
plausibility = if ratio > plausibility_ratio, do: "Plausible", else: "Implausible"
IO.puts str
IO.puts " #{x}: #{nx}; #{y}: #{ny}; Ratio: #{Float.round(ratio,3)}: #{plausibility}"
ratio > plausibility_ratio
end)
end
def countup(binary, regex) do
String.split(binary)
|> Enum.reduce(Map.new, fn word,acc ->
if match = Regex.run(regex, word),
do: Dict.update(acc, hd(match), 1, &(&1+1)), else: acc
end)
end
end
path = hd(System.argv)
IO.inspect RC.task(path)
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