Problem Statement

A consummate number is a non-negative integer that can be formed by some integer N divided by the the digital sum of N.

47 is a consummate number. On the other hand, there are integers that can not be formed by a ratio of any integer over its digital sum. These numbers are known as inconsummate numbers.

62 is an inconsummate number. There is no integer ratio of an integer to its digital sum that will result in 62. The base that a number is expressed in will affect whether it is inconsummate or not. This task will be restricted to base 10.

Let's start with the solution:

task←{
    gen ← ⍳~(⊢(/⍨)⌊=⊢)∘(⊢÷(+/⍎¨∘⍕)¨)∘⍳∘(⊢×9×≢∘⍕)
    incons ← gen 9999
    ⎕←'The first 50 inconsummate numbers:'
    ⎕←5 10⍴50↑incons
    ⎕←'The 1000th inconsummate number:',incons[1000]
}