How to resolve the algorithm Integer comparison step by step in the ALGOL 68 programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Integer comparison step by step in the ALGOL 68 programming language

Table of Contents

Problem Statement

Get two integers from the user. Then,   display a message if the first integer is: the second integer.

Test the condition   for each case separately,   so that   all three comparison operators are used   in the code.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Integer comparison step by step in the ALGOL 68 programming language

Source code in the algol programming language

main: (
  INT a, b;
  read((a, space, b, new line));

  IF a <= b OR a LE b # OR a ≤ b # THEN
    print((a," is less or equal to ", b, new line))
  FI;
  IF a < b OR a LT b THEN
    print((a," is less than ", b, new line))
  ELIF a = b OR a EQ b THEN
    print((a," is equal to ", b, new line))
  ELIF a > b OR a GT b THEN
    print((a," is greater than ", b, new line))
  FI;
  IF a /= b OR a NE b # OR a ≠ b # THEN
    print((a," is not equal to ", b, new line))
  FI;
  IF a >= b OR a GE b # OR a ≥ b # THEN
    print((a," is greater or equal to ", b, new line))
  FI
)

  

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