How to resolve the algorithm Integer comparison step by step in the Joy programming language

Published on 12 May 2024 09:40 PM
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How to resolve the algorithm Integer comparison step by step in the Joy programming language

Table of Contents

Problem Statement

Get two integers from the user. Then,   display a message if the first integer is: the second integer.

Test the condition   for each case separately,   so that   all three comparison operators are used   in the code.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Integer comparison step by step in the Joy programming language

Source code in the joy programming language

#!/usr/local/bin/joy.exe
DEFINE
prompt  == "Please enter a number and : " putchars;
newline == '\n putch;
putln   == put newline.

stdin		    # F
prompt fgets	# S F
10 strtol	    # A F
swap		    # F A
dupd		    # F A A
prompt fgets	# S F A A
10 strtol	    # B F A A
popd		    # B A A
dup		        # B B A A
rollup		    # B A B A
[<] [swap put "is less than "    putchars putln] [] ifte
[=] [swap put "is equal to "     putchars putln] [] ifte
[>] [swap put "is greater than " putchars putln] [] ifte
		        # B A
quit.

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