How to resolve the algorithm Integer comparison step by step in the Octave programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Integer comparison step by step in the Octave programming language
Table of Contents
Problem Statement
Get two integers from the user. Then, display a message if the first integer is: the second integer.
Test the condition for each case separately, so that all three comparison operators are used in the code.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Integer comparison step by step in the Octave programming language
Source code in the octave programming language
printf("Enter a: ");
a = scanf("%d", "C");
printf("Enter b: ");
b = scanf("%d", "C");
if (a > b)
disp("a greater than b");
elseif (a == b)
disp("a equal to b");
elseif (a < b)
disp("a less than b");
endif
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