How to resolve the algorithm Integer comparison step by step in the PHP programming language
How to resolve the algorithm Integer comparison step by step in the PHP programming language
Table of Contents
Problem Statement
Get two integers from the user. Then, display a message if the first integer is: the second integer.
Test the condition for each case separately, so that all three comparison operators are used in the code.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Integer comparison step by step in the PHP programming language
This PHP script prompts the user to enter two integers (int1
and int2
) and then performs a basic comparison between them, printing whether int1
is less than (<
), equal to (=
), or greater than (>
) int2
.
Here's a breakdown:
-
fscanf(STDIN, "%d\n", $int1);
: Reads the user's input from the standard input (STDIN) for the first integer and stores it in the$int1
variable. -
It checks if the input is a valid number using
is_numeric($int1)
. If the input is not numeric, it prints an error message and exits the script with a general error code (1). -
Repeats the process for
$int2
. -
After both inputs are validated as numeric, the script compares them using conditional statements:
if ($int1 < $int2)
checks ifint1
is less thanint2
.if ($int1 == $int2)
checks ifint1
is equal toint2
.if ($int1 > $int2)
checks ifint1
is greater thanint2
.
-
If any of these conditions are true, the corresponding message will be printed.
-
If none of the conditions are met, no message will be printed.
In summary, this script validates user input for two integers, compares them, and informs the user about their relationship using the if
statements.
Source code in the php programming language
<?php
echo "Enter an integer [int1]: ";
fscanf(STDIN, "%d\n", $int1);
if(!is_numeric($int1)) {
echo "Invalid input; terminating.\n";
exit(1); // return w/ general error
}
echo "Enter an integer [int2]: ";
fscanf(STDIN, "%d\n", $int2);
if(!is_numeric($int2)) {
echo "Invalid input; terminating.\n";
exit(1); // return w/ general error
}
// now $int1 and $int2 are numbers.
// for simplicity, this does not explicitly examine types
if($int1 < $int2)
echo "int1 < int2\n";
if($int1 == $int2)
echo "int1 = int2\n";
if($int1 > $int2)
echo "int1 > int2\n";
?>
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