How to resolve the algorithm Integer comparison step by step in the Perl programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Integer comparison step by step in the Perl programming language
Table of Contents
Problem Statement
Get two integers from the user. Then, display a message if the first integer is: the second integer.
Test the condition for each case separately, so that all three comparison operators are used in the code.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Integer comparison step by step in the Perl programming language
Source code in the perl programming language
sub test_num {
my $f = shift;
my $s = shift;
if ($f < $s){
return -1; # returns -1 if $f is less than $s
} elsif ($f > $s) {
return 1; # returns 1 if $f is greater than $s
} elsif ($f == $s) {
# = operator is an assignment
# == operator is a numeric comparison
return 0; # returns 0 $f is equal to $s
};
};
sub test_num {
return $_[0] <=> $_[1];
};
# Get input, test and display
print "Enter two integers: ";
($x, $y) = split ' ', <>;
print $x, (" is less than ", " is equal to ",
" is greater than ")[test_num($x, $y) + 1], $y, "\n";
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