How to resolve the algorithm Integer comparison step by step in the Smalltalk programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Integer comparison step by step in the Smalltalk programming language
Table of Contents
Problem Statement
Get two integers from the user. Then, display a message if the first integer is: the second integer.
Test the condition for each case separately, so that all three comparison operators are used in the code.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Integer comparison step by step in the Smalltalk programming language
Source code in the smalltalk programming language
| a b |
'a = ' display. a := (stdin nextLine asInteger).
'b = ' display. b := (stdin nextLine asInteger).
( a > b ) ifTrue: [ 'a greater than b' displayNl ].
( a < b ) ifTrue: [ 'a less than b' displayNl ].
( a = b ) ifTrue: [ 'a is equal to b' displayNl ].
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