How to resolve the algorithm Integer sequence step by step in the Fortran programming language
How to resolve the algorithm Integer sequence step by step in the Fortran programming language
Table of Contents
Problem Statement
Create a program that, when run, would display all integers from 1 to ∞ (or any relevant implementation limit), in sequence (i.e. 1, 2, 3, 4, etc) if given enough time.
An example may not be able to reach arbitrarily-large numbers based on implementations limits. For example, if integers are represented as a 32-bit unsigned value with 0 as the smallest representable value, the largest representable value would be 4,294,967,295. Some languages support arbitrarily-large numbers as a built-in feature, while others make use of a module or library. If appropriate, provide an example which reflect the language implementation's common built-in limits as well as an example which supports arbitrarily large numbers, and describe the nature of such limitations—or lack thereof.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Integer sequence step by step in the Fortran programming language
Source code in the fortran programming language
program Intseq
implicit none
integer, parameter :: i64 = selected_int_kind(18)
integer(i64) :: n = 1
! n is declared as a 64 bit signed integer so the program will display up to
! 9223372036854775807 before overflowing to -9223372036854775808
do
print*, n
n = n + 1
end do
end program
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