Step by Step solution about How to resolve the algorithm Interactive programming (repl) step by step in the Ruby programming language

The given Ruby code defines a method named f that takes three parameters: string1, string2, and separator. Here's how this code works:

1. def f(string1, string2, separator): This line defines a method named f that accepts three parameters: string1 (a string), string2 (a string), and separator (a string that will be used to separate the two input strings).

2. [string1, '', string2].join(separator): Inside the method, an array is created containing three elements: string1, an empty string '', and string2. The join method is then called on this array with the separator as an argument. The join method combines the elements of the array into a single string, using the separator in between each element.

3. end: This line marks the end of the f method definition.

The code demonstrates how to use the join method to concatenate two strings with a separator in between. Let's break down the example:

f('Rosetta', 'Code', ':'): This line calls the f method with three arguments: 'Rosetta' as string1, 'Code' as string2, and ':' as separator.

The join method is called on the array [string1, '', string2], which contains 'Rosetta', an empty string, and 'Code'. The join method uses the ':' separator to combine the elements, resulting in the string 'Rosetta::Code'.

The final output is "Rosetta::Code," which demonstrates how the f method can be used to concatenate two strings with a specified separator.

$ irb
irb(main):001:0> def f(string1, string2, separator)
irb(main):002:1>     [string1, '', string2].join(separator)
irb(main):003:1> end
=> :f
irb(main):004:0> f('Rosetta', 'Code', ':')
=> "Rosetta::Code"
irb(main):005:0> exit
$