How to resolve the algorithm Inverted syntax step by step in the Mercury programming language

Published on 12 May 2024 09:40 PM
#Mercury

How to resolve the algorithm Inverted syntax step by step in the Mercury programming language

Table of Contents

Problem Statement

Inverted syntax with conditional expressions In traditional syntax conditional expressions are usually shown before the action within a statement or code block: In inverted syntax, the action is listed before the conditional expression in the statement or code block: Inverted syntax with assignment In traditional syntax, assignments are usually expressed with the variable appearing before the expression: In inverted syntax, the expression appears before the variable: Task The task is to demonstrate support for inverted syntax forms within the language by showing both the traditional and inverted forms.

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Step by Step solution about How to resolve the algorithm Inverted syntax step by step in the Mercury programming language

Source code in the mercury programming language

:- pred progress(int::in, int::in, int::out, int::out) is det.
progress(Past, Future, At, Total) :-
	At = Past + 1,
	Total = Past + Future.

progress(Past, Future, At, Total) :-
        Past + Future = Total,
        Past + 1 = At.

:- func example(int) = string.
example(N) = S :-
        from_int(N) = S0,
        pad_left(S0, '0', 3, S).

example(N) = S :-
        pad_left(S0, '0', 3, S),
        from_int(N) = S0.

main(IO0, IO) :-
        io.write_string("Hello, ", IO0, IO1),
        io.write_string("world!\n", IO1, IO).

main(!IO) :-
        io.write_string("Hello, ", !IO),
        io.write_string("world!\n", !IO).

main(!IO) :-
        io.write_string(X, !IO), io.nl(!IO),
        some_long_uninteresting_thing(X).

% this is the same:
main(!IO) :-
        some_long_uninteresting_thing(X),
        io.write_string(X, !IO), io.nl(!IO).

% but this is different!
main(!IO) :-
        io.nl(!IO), io.write_string(X, !IO),
        some_long_uninteresting_thing(X).

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