How to resolve the algorithm Jewels and stones step by step in the Factor programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Jewels and stones step by step in the Factor programming language
Table of Contents
Problem Statement
Create a function which takes two string parameters: 'stones' and 'jewels' and returns an integer. Both strings can contain any number of upper or lower case letters. However, in the case of 'jewels', all letters must be distinct. The function should count (and return) how many 'stones' are 'jewels' or, in other words, how many letters in 'stones' are also letters in 'jewels'.
Note that: So, for example, if passed "aAAbbbb" for 'stones' and "aA" for 'jewels', the function should return 3. This task was inspired by this problem.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Jewels and stones step by step in the Factor programming language
Source code in the factor programming language
USING: kernel prettyprint sequences ;
: count-jewels ( stones jewels -- n ) [ member? ] curry count ;
"aAAbbbb" "aA"
"ZZ" "z" [ count-jewels . ] 2bi@
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