How to resolve the algorithm Knapsack problem/0-1 step by step in the Tcl programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Knapsack problem/0-1 step by step in the Tcl programming language

Table of Contents

Problem Statement

A tourist wants to make a good trip at the weekend with his friends. They will go to the mountains to see the wonders of nature, so he needs to pack well for the trip. He has a good knapsack for carrying things, but knows that he can carry a maximum of only 4kg in it,   and it will have to last the whole day. He creates a list of what he wants to bring for the trip but the total weight of all items is too much. He then decides to add columns to his initial list detailing their weights and a numerical value representing how important the item is for the trip.

Here is the list:

The tourist can choose to take any combination of items from the list, but only one of each item is available. He may not cut or diminish the items, so he can only take whole units of any item.

Show which items the tourist can carry in his knapsack so that their total weight does not exceed 400 dag [4 kg],   and their total value is maximized. [dag = decagram = 10 grams]

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Knapsack problem/0-1 step by step in the Tcl programming language

Source code in the tcl programming language

# The list of items to consider, as list of lists
set items {
    {map			9	150}
    {compass			13	35}
    {water			153	200}
    {sandwich			50	160}
    {glucose			15	60}
    {tin			68	45}
    {banana			27	60}
    {apple			39	40}
    {cheese			23	30}
    {beer			52	10}
    {{suntan cream}		11	70}
    {camera			32	30}
    {t-shirt			24	15}
    {trousers			48	10}
    {umbrella			73	40}
    {{waterproof trousers}	42	70}
    {{waterproof overclothes}	43	75}
    {note-case			22	80}
    {sunglasses			7	20}
    {towel			18	12}
    {socks			4	50}
    {book			30	10}
}

# Simple extraction functions
proc names {chosen} {
    set names {}
    foreach item $chosen {lappend names [lindex $item 0]}
    return $names
}
proc weight {chosen} {
    set weight 0
    foreach item $chosen {incr weight [lindex $item 1]}
    return $weight
}
proc value {chosen} {
    set value 0
    foreach item $chosen {incr value [lindex $item 2]}
    return $value
}

# Recursive function for searching over all possible choices of items
proc knapsackSearch {items {chosen {}}} {
    # If we've gone over the weight limit, stop now
    if {[weight $chosen] > 400} {
	return
    }
    # If we've considered all of the items (i.e., leaf in search tree)
    # then see if we've got a new best choice.
    if {[llength $items] == 0} {
	global best max
	set v [value $chosen]
	if {$v > $max} {
	    set max $v
	    set best $chosen
	}
	return
    }
    # Branch, so recurse for chosing the current item or not
    set this [lindex $items 0]
    set rest [lrange $items 1 end]
    knapsackSearch $rest $chosen
    knapsackSearch $rest [lappend chosen $this]
}

# Initialize a few global variables
set best {}
set max 0
# Do the brute-force search
knapsackSearch $items
# Pretty-print the results
puts "Best filling has weight of [expr {[weight $best]/100.0}]kg and score [value $best]"
puts "Best items:\n\t[join [lsort [names $best]] \n\t]"


  

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