Step by Step solution about How to resolve the algorithm Knight's tour step by step in the Julia programming language

This code solves the Hidato puzzle defined in the variable chessboard. A Hidato puzzle is a puzzle where you have to fill a grid with numbers from 1 to the size of the grid, such that each number is adjacent to the previous and next number in the sequence. The code first defines the knightmoves array, which contains all the possible moves a knight can make in a chess game. Then it calls the hidatoconfigure function, which takes the chessboard string as input and returns a tuple containing the board array, the maxmoves integer variable, the fixed array, and the starts tuple containing the starting row and column. The board array is a 2D array of integers representing the puzzle grid, where 0 represents an empty cell. The maxmoves integer variable is the maximum number of moves allowed to solve the puzzle. The fixed array is a 2D array of booleans indicating which cells are fixed and cannot be changed. The starts tuple contains the starting row and column of the puzzle. The code then calls the printboard function to print the initial state of the board, and then calls the hidatosolve function to solve the puzzle. The hidatosolve function takes the board, maxmoves, knightmoves, fixed, sr, sc, and m arguments, where sr and sc are the starting row and column, and m is the current move number. The hidatosolve function uses a recursive backtracking algorithm to solve the puzzle. It first checks if the current move number is greater than the maximum number of moves allowed, and if so, it returns false. It then checks if the current cell is fixed, and if so, it checks if the current move number is equal to the value in the fixed cell. If the current move number is not equal to the value in the fixed cell, the function returns false. If the current cell is not fixed, the function loops through all the possible moves from the current cell, and for each move, it checks if the move is valid (i.e. the cell is empty and not fixed), and if so, it recursively calls the hidatosolve function to solve the puzzle starting from the new cell. If any of the recursive calls return true, the function returns true, indicating that the puzzle has been solved. If none of the recursive calls return true, the function returns false, indicating that the puzzle could not be solved. The code then calls the printboard function to print the solved puzzle.

using .Hidato       # Note that the . here means to look locally for the module rather than in the libraries

const chessboard = """
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0
 0 0 0 0 0 0 0 0 """

const knightmoves = [[-2, -1], [-2, 1], [-1, -2], [-1, 2], [1, -2], [1, 2], [2, -1], [2, 1]]

board, maxmoves, fixed, starts = hidatoconfigure(chessboard)
printboard(board, " 0", "  ")
hidatosolve(board, maxmoves, knightmoves, fixed, starts[1][1], starts[1][2], 1)
printboard(board)