How to resolve the algorithm Knuth's algorithm S step by step in the Kotlin programming language
How to resolve the algorithm Knuth's algorithm S step by step in the Kotlin programming language
Table of Contents
Problem Statement
This is a method of randomly sampling n items from a set of M items, with equal probability; where M >= n and M, the number of items is unknown until the end. This means that the equal probability sampling should be maintained for all successive items > n as they become available (although the content of successive samples can change).
Note: A class taking n and generating a callable instance/function might also be used.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Knuth's algorithm S step by step in the Kotlin programming language
The provided Kotlin code demonstrates the implementation of a "Sample of N" (SOfN) algorithm, which is designed to maintain a sample of a fixed size (n) as new items are processed. When the sample size exceeds n, new items may randomly replace existing ones to maintain the sample size.
Here's a detailed explanation of the code:
Version 1.2.51
-
The first version of the code defines a class called
SOfN
that takes a single parametern
, which represents the sample size. -
The class has three main properties:
sample
: AnArrayList
that stores the actual sample of items.i
: An integer that keeps track of the number of items processed so far.process
: A function that takes an item as input and returns the current sample. Here's how this function works:- If the number of items processed so far
(i)
is less than or equal to the sample size(n)
, the item is added to the sample. - Otherwise, a random index within the sample is generated. If that index is less than
n
, the item at that index is replaced with the new item. - In both cases, the updated sample is returned.
- If the number of items processed so far
-
The
main
function creates an integer arraybin
with a size of 10. It then iterates from 1 to 100,000, performing the following steps for each iteration:- It creates a new instance of
SOfN
with a sample size of 3. - For each integer from 0 to 8, it calls the
process
function of theSOfN
instance, passing the integer as the input. - Finally, it calls
process
again with the number 9, and increments the corresponding element in thebin
array for each element in the returned sample.
- It creates a new instance of
After all the iterations are complete, the main
function prints the contents of the bin
array, which shows the frequency of each number from 0 to 9 appearing in the sample.
Version 1.2.51
- This version of the code utilizes a slightly different approach using higher-order functions.
- It defines a function
SOfNCreator
that takes a sample sizen
as input and returns a function that takes an item of typeT
and returns a list of typeT
. - The returned function, which is a closure, maintains an internal state (the sample) and behaves similarly to the
process
function in the previous version. - The
main
function is essentially the same as in the previous version, except that it uses theSOfNCreator
function to create a new sample of size 3 for each iteration.
Source code in the kotlin programming language
// version 1.2.51
import java.util.Random
val rand = Random()
class SOfN<T>(val n: Int) {
private val sample = ArrayList<T>(n)
private var i = 0
fun process(item: T): List<T> {
if (++i <= n)
sample.add(item)
else if (rand.nextInt(i) < n)
sample[rand.nextInt(n)] = item
return sample
}
}
fun main(args: Array<String>) {
val bin = IntArray(10)
(1..100_000).forEach {
val sOfn = SOfN<Int>(3)
for (d in 0..8) sOfn.process(d)
for (s in sOfn.process(9)) bin[s]++
}
println(bin.contentToString())
}
// version 1.2.51
import java.util.Random
val rand = Random()
fun <T> SOfNCreator(n: Int): (T) -> List<T> {
val sample = ArrayList<T>(n)
var i = 0
return {
if (++i <= n)
sample.add(it)
else if (rand.nextInt(i) < n)
sample[rand.nextInt(n)] = it
sample
}
}
fun main(args: Array<String>) {
val bin = IntArray(10)
(1..100_000).forEach {
val sOfn = SOfNCreator<Int>(3)
for (d in 0..8) sOfn(d)
for (s in sOfn(9)) bin[s]++
}
println(bin.contentToString())
}
You may also check:How to resolve the algorithm Compare a list of strings step by step in the S-lang programming language
You may also check:How to resolve the algorithm Function definition step by step in the ALGOL-M programming language
You may also check:How to resolve the algorithm The Twelve Days of Christmas step by step in the F# programming language
You may also check:How to resolve the algorithm Polynomial long division step by step in the ALGOL 68 programming language
You may also check:How to resolve the algorithm Active Directory/Search for a user step by step in the Eiffel programming language