How to resolve the algorithm Last Friday of each month step by step in the Nanoquery programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Last Friday of each month step by step in the Nanoquery programming language
Table of Contents
Problem Statement
Write a program or a script that returns the date of the last Fridays of each month of a given year. The year may be given through any simple input method in your language (command line, std in, etc).
Example of an expected output:
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Last Friday of each month step by step in the Nanoquery programming language
Source code in the nanoquery programming language
import Nanoquery.Util
// a function to check if a year is a leap year
def isLeapYear(year)
if (year % 100 = 0)
return (year % 400 = 0)
else
return (year % 4 = 0)
end
end
// a function to format 1-digit numbers as "0x"
def form(num)
if (num > 9)
return str(num)
else
return "0" + str(num)
end
end
// get a year from the console
print "enter year: "
year = int(input())
// build a list of the expected amount of days for each month
days = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
if isLeapYear($year)
days[1] = 29
end
// loop through each month
for month in range(1, len($days))
// loop through each day of the month
friday = null
for day in range(1, days[month - 1])
// create a date object for this date
date = new(Date)
date.setYear(year).setMonth(month).setDay(day)
// check if it's a friday
if (date.getDayOfWeek() = "Friday")
// if it is, keep it
friday = new(Date, date)
end
end for
// display the last friday found
print friday.getYear() + "-"
print form(friday.getMonth()) + "-"
println form(friday.getDay())
end
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