How to resolve the algorithm Last letter-first letter step by step in the Ursala programming language

Published on 12 May 2024 09:40 PM
#Ursala

How to resolve the algorithm Last letter-first letter step by step in the Ursala programming language

Table of Contents

Problem Statement

A certain children's game involves starting with a word in a particular category.   Each participant in turn says a word, but that word must begin with the final letter of the previous word.   Once a word has been given, it cannot be repeated.   If an opponent cannot give a word in the category, they fall out of the game.

For example, with   "animals"   as the category,

Take the following selection of 70 English Pokemon names   (extracted from   Wikipedia's list of Pokemon)   and generate the/a sequence with the highest possible number of Pokemon names where the subsequent name starts with the final letter of the preceding name. No Pokemon name is to be repeated.

Extra brownie points for dealing with the full list of   646   names.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Last letter-first letter step by step in the Ursala programming language

Source code in the ursala programming language

#import std

mon = 

~&*~ sep`  mat`  -[
   audino bagon baltoy banette bidoof braviary bronzor carracosta charmeleon
   cresselia croagunk darmanitan deino emboar emolga exeggcute gabite
   girafarig gulpin haxorus heatmor heatran ivysaur jellicent jumpluff kangaskhan
   kricketune landorus ledyba loudred lumineon lunatone machamp magnezone mamoswine
   nosepass petilil pidgeotto pikachu pinsir poliwrath poochyena porygon2
   porygonz registeel relicanth remoraid rufflet sableye scolipede scrafty seaking
   sealeo silcoon simisear snivy snorlax spoink starly tirtouga trapinch treecko
   tyrogue vigoroth vulpix wailord wartortle whismur wingull yamask]-

poke = @iiDrzhK16rlXOASK24PiX ~&llrHiFPrYX^=rxS^|\~&iNCS *=+ ~&rlwNrlCQ^*D/~&+ @h

#show+

example = ~&h poke mon

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