Step by Step solution about How to resolve the algorithm Leap year step by step in the C# programming language

The provided C# code uses a foreach loop to iterate through an array of years and checks if each year is a leap year using the DateTime.IsLeapYear method.

A breakdown of the code:

1. Array of Years:

int[] years = { 1900, 1994, 1996, DateTime.Now.Year };

This initializes an array named years with four year values: 1900, 1994, 1996, and the current year obtained from DateTime.Now.Year.

2. Loop and Leap Year Check:

foreach (var year in years)
{
   Console.WriteLine("{0} is {1}a leap year.",
                     year,
                     DateTime.IsLeapYear(year) ? string.Empty : "not ");
}

This foreach loop iterates through each year in the years array. For each year, it checks if it's a leap year using the DateTime.IsLeapYear method. If the method returns true, it means the year is a leap year, so it prints a message indicating that without the word "not." Otherwise, it prints a message indicating that the year is not a leap year with the word "not."

3. Output: The code will output the results to the console, indicating whether each year is a leap year or not. For example:

1900 is not a leap year.
1994 is a leap year.
1996 is a leap year.
2023 is not a leap year.

In summary, this code iterates through a list of years, checks if they are leap years, and then prints the results to the console, providing information about whether each year is a leap year or not.

using System;

class Program
{
    static void Main()
    {
        foreach (var year in new[] { 1900, 1994, 1996, DateTime.Now.Year })
        {
            Console.WriteLine("{0} is {1}a leap year.",
                              year,
                              DateTime.IsLeapYear(year) ? string.Empty : "not ");
        }
    }
}