How to resolve the algorithm Leap year step by step in the Neko programming language

Published on 12 May 2024 09:40 PM
#Neko

How to resolve the algorithm Leap year step by step in the Neko programming language

Table of Contents

Problem Statement

Determine whether a given year is a leap year in the Gregorian calendar.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Leap year step by step in the Neko programming language

Source code in the neko programming language

/**
 
Leap year, in Neko

**/

var leapyear = function(y) return ($not(y % 4) && $istrue(y % 100) || $not(y % 400))

var tests = $array(2000, 1997, 1996, 1994, 1990, 1980, 1900)
var cnt = $asize(tests)
while (cnt -= 1) >= 0 $print(tests[cnt], if leapyear(tests[cnt]) " is" else " is not", " a leapyear", "\n")

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